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anonymous
 4 years ago
I need help please....
Find the domain of the rational function F(x)=2(x^24)/3(x^2+4x+4)
I have factored them correctly but it said after I factored them I shouldn't reduce any common factors and should find the domain of the function using its factored form and that I need to state the domain in interval notation. I am lost and do not know how to work this out apparently
anonymous
 4 years ago
I need help please.... Find the domain of the rational function F(x)=2(x^24)/3(x^2+4x+4) I have factored them correctly but it said after I factored them I shouldn't reduce any common factors and should find the domain of the function using its factored form and that I need to state the domain in interval notation. I am lost and do not know how to work this out apparently

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nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1\[x^2+4x+4\neq0 \] \[(x+2)^2\neq0\] so the domain interval is:

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1\[x^2+4x+4\neq0 \] \[(x+2)^2\neq0\] so the domain interval is: \[x \in(\infty,2)\cup(2,+\infty)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Check your nos nena..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am not understanding...i was told to find the domain of the function using the factored form F(x)=[2(x2)(x+2)]/[3(x+2)(x+2)]....how do I work this out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Once factored you must use fact the Denominator cannot be zero for any real no

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1it's ok...:D kcbrosell what part you don't understand?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0all of it I am failing this class big time...I dont understand all the factoring or how to put it into and equation and so on

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1every time you want to find the domain of the function which is given in fraction form denominator must not be equal to zero, so when you factor x^2+4x+4 you get the result I wrote.....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am not understanding how you get to the result u wrote

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1well it's a basic binomial formula which you must know if you want to do some serious math in the future....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got to this point x^24=(x2)(x+2) & x^2+4x+4=(x^2+2)

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.1you got wrong x^2+2x+4...it is (x+2)^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0o crud...so after I get that worked out do I have to put them into another equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328644954475:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if terms like (x+2) cancel, there would normally be a "hole" in the graph...but note that there is still a (x+2) in the denominator, so you must set it equal to zero and solve....this is the value that won't work....so the domain is all of the other numbers....the numbers less than 2 and the numbers greater than 2.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so then my answer would be (oo, 2) (2, oo)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it all has to do with your neg and pos and how they factor out

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0think about what would make the denominator equal to zero...you are correct you often times must factor first to be able to tell.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay i thinki understand it a little bit better now thank you for your help
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