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anonymous

  • 4 years ago

I need help please.... Find the domain of the rational function F(x)=-2(x^2-4)/3(x^2+4x+4) I have factored them correctly but it said after I factored them I shouldn't reduce any common factors and should find the domain of the function using its factored form and that I need to state the domain in interval notation. I am lost and do not know how to work this out apparently

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  1. nenadmatematika
    • 4 years ago
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    \[x^2+4x+4\neq0 \] \[(x+2)^2\neq0\] so the domain interval is:

  2. nenadmatematika
    • 4 years ago
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    \[x^2+4x+4\neq0 \] \[(x+2)^2\neq0\] so the domain interval is: \[x \in(-\infty,-2)\cup(-2,+\infty)\]

  3. anonymous
    • 4 years ago
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    R-{-2}

  4. anonymous
    • 4 years ago
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    Check your nos nena..

  5. nenadmatematika
    • 4 years ago
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    to check what?

  6. anonymous
    • 4 years ago
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    I am not understanding...i was told to find the domain of the function using the factored form F(x)=[-2(x-2)(x+2)]/[3(x+2)(x+2)]....how do I work this out

  7. anonymous
    • 4 years ago
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    Sorry my bad

  8. anonymous
    • 4 years ago
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    Once factored you must use fact the Denominator cannot be zero for any real no

  9. nenadmatematika
    • 4 years ago
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    it's ok...:D kcbrosell what part you don't understand?

  10. anonymous
    • 4 years ago
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    all of it I am failing this class big time...I dont understand all the factoring or how to put it into and equation and so on

  11. nenadmatematika
    • 4 years ago
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    every time you want to find the domain of the function which is given in fraction form denominator must not be equal to zero, so when you factor x^2+4x+4 you get the result I wrote.....

  12. anonymous
    • 4 years ago
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    I am not understanding how you get to the result u wrote

  13. nenadmatematika
    • 4 years ago
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    well it's a basic binomial formula which you must know if you want to do some serious math in the future....

  14. anonymous
    • 4 years ago
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    I got to this point x^2-4=(x-2)(x+2) & x^2+4x+4=(x^2+2)

  15. nenadmatematika
    • 4 years ago
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    you got wrong x^2+2x+4...it is (x+2)^2

  16. anonymous
    • 4 years ago
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    o crud...so after I get that worked out do I have to put them into another equation

  17. anonymous
    • 4 years ago
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    |dw:1328644954475:dw|

  18. anonymous
    • 4 years ago
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    if terms like (x+2) cancel, there would normally be a "hole" in the graph...but note that there is still a (x+2) in the denominator, so you must set it equal to zero and solve....this is the value that won't work....so the domain is all of the other numbers....the numbers less than -2 and the numbers greater than -2.

  19. anonymous
    • 4 years ago
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    so then my answer would be (-oo, -2) (-2, oo)

  20. anonymous
    • 4 years ago
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    yes.

  21. anonymous
    • 4 years ago
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    so it all has to do with your neg and pos and how they factor out

  22. anonymous
    • 4 years ago
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    think about what would make the denominator equal to zero...you are correct you often times must factor first to be able to tell.

  23. anonymous
    • 4 years ago
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    okay i thinki understand it a little bit better now thank you for your help

  24. anonymous
    • 4 years ago
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    :)

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