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anonymous
 4 years ago
Open Physics Challenge:
One mole of a gas is put under weightless piston of a vertical cylinder at temprature T.the space over opens into atmosphere.Initially piston was in equilibrium.How much work should be odn by some external force to increase isothermally the volume under piston twice the volume?
anonymous
 4 years ago
Open Physics Challenge: One mole of a gas is put under weightless piston of a vertical cylinder at temprature T.the space over opens into atmosphere.Initially piston was in equilibrium.How much work should be odn by some external force to increase isothermally the volume under piston twice the volume?

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nikvist
 4 years ago
Best ResponseYou've already chosen the best response.1\[pV=n_mRT\quad,\quad p=n_mRT\frac{1}{V}\]\[A=\int pdV=n_mRT\int\limits_{V_0}^{2V_0}\frac{dV}{V}=n_mRT\cdot\ln{2}\quad(n_m=1mol)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no try to find out what you missed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ans is \[n_mRT(1\ln2)\] You ignored work done against atmosphere

nikvist
 4 years ago
Best ResponseYou've already chosen the best response.1\[p_0V_0=pV=n_mRT\]\[A=\int(p_0p)dV=\int p_0dV\int pdV=\]\[=p_0\int\limits_{V_0}^{2V_0}dVn_mRT\int\limits_{V_0}^{2V_0}\frac{dV}{V}=p_0V_0n_mRT\cdot\ln{2}=\]\[=n_mRT(1\ln{2})\]Now is OK
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