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anonymous

  • 4 years ago

Solve cos^-1(3x)-6cos3x=4sin3x

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  1. anonymous
    • 4 years ago
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    |dw:1328646687263:dw|

  2. anonymous
    • 4 years ago
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    is it \[\cos^{-1}3x ------------ or ---------- \frac{1}{\cos 3x}\]

  3. anonymous
    • 4 years ago
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    Aren't they the same thing?

  4. anonymous
    • 4 years ago
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    no

  5. anonymous
    • 4 years ago
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    Then the first one .

  6. anonymous
    • 4 years ago
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    1 - 6 cos^2 3x = 4 sin3x cos3x = 2 sin 6x - ive assumed 1 / cos 3x

  7. anonymous
    • 4 years ago
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    \[2\cos^23x=1+\cos6x\]

  8. anonymous
    • 4 years ago
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    Can you show steps?

  9. anonymous
    • 4 years ago
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    no

  10. anonymous
    • 4 years ago
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    Wonderful .

  11. anonymous
    • 4 years ago
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    this time do yourself

  12. anonymous
    • 4 years ago
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    And what do you think I would be doing if I had any idea on how to solve them?

  13. anonymous
    • 4 years ago
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    When you are trying you are progressing

  14. anonymous
    • 4 years ago
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    Sleeping is too mainstream anyways . Thank you for your help .

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spraguer (Moderator)
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