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jooceeeox Group Title

graph the parabola y=3.6(x-1)^2-4

  • 2 years ago
  • 2 years ago

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  1. Hero Group Title
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    Use a calculator

    • 2 years ago
  2. jooceeeox Group Title
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    i dont have a graphing calculator... ):

    • 2 years ago
  3. Hero Group Title
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    You should find one

    • 2 years ago
  4. jooceeeox Group Title
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    tell me about it... we're not allowed to use them anyway, so it would be a waste of money!

    • 2 years ago
  5. Sandeez Group Title
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    y=3.6(x-1)^2-4 first, look at what y=x^2 looks like. the numbers around it change the shape and location of the parabola. so -4 is the intercept, moving the center down. the -1 moves the center to the right. 3.6 measures how steep the parabola is. once you understand that, you can start to conceptually understand the graph. to start graphing it, find all the intercepts when y=0, what is x? when x=0, what is y?

    • 2 years ago
  6. jooceeeox Group Title
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    x=0.4?

    • 2 years ago
  7. Sandeez Group Title
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    not quite. almost. plug in 0 for x. y=-0.4 so then plot (0, -.04) that is one point on your parabola. now you need more intercepts and the min.

    • 2 years ago
  8. Sandeez Group Title
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    sorry. correction: (0,-0.4) not .04

    • 2 years ago
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