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jooceeeox

  • 2 years ago

graph the parabola y=3.6(x-1)^2-4

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  1. Hero
    • 2 years ago
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    Use a calculator

  2. jooceeeox
    • 2 years ago
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    i dont have a graphing calculator... ):

  3. Hero
    • 2 years ago
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    You should find one

  4. jooceeeox
    • 2 years ago
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    tell me about it... we're not allowed to use them anyway, so it would be a waste of money!

  5. Sandeez
    • 2 years ago
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    y=3.6(x-1)^2-4 first, look at what y=x^2 looks like. the numbers around it change the shape and location of the parabola. so -4 is the intercept, moving the center down. the -1 moves the center to the right. 3.6 measures how steep the parabola is. once you understand that, you can start to conceptually understand the graph. to start graphing it, find all the intercepts when y=0, what is x? when x=0, what is y?

  6. jooceeeox
    • 2 years ago
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    x=0.4?

  7. Sandeez
    • 2 years ago
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    not quite. almost. plug in 0 for x. y=-0.4 so then plot (0, -.04) that is one point on your parabola. now you need more intercepts and the min.

  8. Sandeez
    • 2 years ago
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    sorry. correction: (0,-0.4) not .04

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