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anonymous

  • 4 years ago

Find the indefinite integral of (5cosx-2sec^2x)dx

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  1. amistre64
    • 4 years ago
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    who lost it?

  2. amistre64
    • 4 years ago
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    its a sum so we could just find the int of each term

  3. amistre64
    • 4 years ago
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    sec^2 might be tricky tho

  4. amistre64
    • 4 years ago
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    tan goes to sec^2 tho so not all that tricky

  5. Mr.Math
    • 4 years ago
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    Does "goes to" mean "is the integral of"?

  6. amistre64
    • 4 years ago
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    derivatives are down to me; and ints are up; tan goes down to sec^2 in my mind

  7. Mr.Math
    • 4 years ago
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    Hmm interesting :-D

  8. amistre64
    • 4 years ago
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    might be the power thing; x^3 does down a degree ...

  9. amistre64
    • 4 years ago
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    5cos goes up to 5sin -2sec^2 goes up to -2tan then we tack on the +C for indefininity

  10. anonymous
    • 4 years ago
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    I can't get it... :/ I know the integral of cosine is sinx+c and the derivative of sec^2x is tanx+c

  11. anonymous
    • 4 years ago
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    *integral

  12. amistre64
    • 4 years ago
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    then thats it; the +Cs just merge into some uber constant

  13. amistre64
    • 4 years ago
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    \[\int (5cos(x)-2sec^2(x))dx\] \[\int (5cos(x))dx-\int (2sec^2(x))dx\] \[5sin(x)+c_1-2tan(x)+c_2\] \[5sin(x)+-2tan(x)+C\]

  14. anonymous
    • 4 years ago
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    THANKS!

  15. amistre64
    • 4 years ago
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    yw

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