Find the indefinite integral of (5cosx-2sec^2x)dx

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Find the indefinite integral of (5cosx-2sec^2x)dx

Mathematics
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who lost it?
its a sum so we could just find the int of each term
sec^2 might be tricky tho

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Other answers:

tan goes to sec^2 tho so not all that tricky
Does "goes to" mean "is the integral of"?
derivatives are down to me; and ints are up; tan goes down to sec^2 in my mind
Hmm interesting :-D
might be the power thing; x^3 does down a degree ...
5cos goes up to 5sin -2sec^2 goes up to -2tan then we tack on the +C for indefininity
I can't get it... :/ I know the integral of cosine is sinx+c and the derivative of sec^2x is tanx+c
*integral
then thats it; the +Cs just merge into some uber constant
\[\int (5cos(x)-2sec^2(x))dx\] \[\int (5cos(x))dx-\int (2sec^2(x))dx\] \[5sin(x)+c_1-2tan(x)+c_2\] \[5sin(x)+-2tan(x)+C\]
THANKS!
yw

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