A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • 4 years ago

A droplet of water flew vertically from a hot spring geyser at an initial speed of 40 m/s. The approximate height (h), in metres, that the droplet will reach, in (t) seconds is modelled by h = -5t² + 40t. How long before the droplet will reach the ground? Determine the maximum height reached by the droplet of water.

  • This Question is Closed
  1. y2o2
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    1) let h = 0 so -5t²+40t = 0 t(-5t+40) = 0 t = 0(refused) or t =8 sec 2) Maximum height is the vertex of the function calculate the x coordinate of the vertex = -b/2a = -40/-10 = 4 sec. calculate the x coordinate of the vertex = f(-b/2a) = f(4) = -5(4)² + 40(4) = 80 m. So max. Height is 80 meters

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.