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anonymous
 4 years ago
how to graph y=f(x)+2
with this graph
http://mathgraphs.com/plg5e/plg5emg01d01001.pdf
anonymous
 4 years ago
how to graph y=f(x)+2 with this graph http://mathgraphs.com/plg5e/plg5emg01d01001.pdf

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phi
 4 years ago
Best ResponseYou've already chosen the best response.0you get the same curve, but slid up 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it would be 2=f(x)+2?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0they want you to graph y= f(x)+2 that means put dots on the graph at certain points. For example, you put a dot at x= 0 y= 1+2=1 that is 2 up from where the original dot is. then connect the dots

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i see what your saying. but do i use the points given to me or do i choose my own?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0the instructions say use the graph of f. So you have to use f(x) that means find where the dot is for x=0 (it is at y=1), add 2 to the y value, and plot it. that is what y= f(x)+2 means. Do it for every x where f(x) has a dot

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay i see. thank you very much

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0x is always constant correct

phi
 4 years ago
Best ResponseYou've already chosen the best response.0you do not change the x, just the y value.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay. im doing y=f(x) using the same graph so with (0,1) x=0 y=(1) ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0correction *with (0,1)

phi
 4 years ago
Best ResponseYou've already chosen the best response.0OK, that's right. you should get a graph that slopes down

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would it not be the same as the original though

phi
 4 years ago
Best ResponseYou've already chosen the best response.0how can it be the same when you are changing it? plot it and see.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the points come out on the same line as the first equation (y=f(x)+2)

phi
 4 years ago
Best ResponseYou've already chosen the best response.0what points did you get? here are the first two pair: original new 0,1 0,1 1, 0 1,0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got the same thing also. i guess i am just confusing myself

phi
 4 years ago
Best ResponseYou've already chosen the best response.0what did you get for the rest of the points?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(3,1),(4,2) i get it now

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now with the same graph how would y=f(x2) i understand with (0,1) x=2+(0)=2 but how would y= work out?

phi
 4 years ago
Best ResponseYou've already chosen the best response.0y= f(x2) is shorthand for pick x, for example x=2, now find the y value of f(x2)= f(0) which is 1 (using the original function). so your point is (2,1) for x=3, find the yvalue of f(32)= f(1) = 0, so your next pair is (3,0) and so on. Notice that you can not find values for x=0 or x=1 because you do not know what f(2) or f(1) is. But you can find numbers for x=6. The whole graph is shifted to the right 2 spaces.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so if i have (3,4) , y=f(x2) then say x=3 , and to find y i would substitute the x. y=32=1so my answer would be (3,1)

phi
 4 years ago
Best ResponseYou've already chosen the best response.0This is not right: y=32 what you want is y= f(32) that means y= f(1). y=f(1) means look at your graph and at x=1 what is the graph's y value? In your graph it is 0. so the answer is (3,0)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i don't really get it. in my precall book for point (0,1) , y=f(x2) x=0 y=f(02)....y=f(2) (0,2) ^^i feel this is incorrect

phi
 4 years ago
Best ResponseYou've already chosen the best response.0You must not be reading my posts very closely. See up above. But you are doing it correctly. You do not have any point to plot at x=0. No problem. Keep going until you get an x that works, and then keep going....

phi
 4 years ago
Best ResponseYou've already chosen the best response.0btw f(2) is NOT2, it is undefined. your point is (0, ???). Try x=2, which is the first x that will work.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay il review everything over. oh okay . thank you again

phi
 4 years ago
Best ResponseYou've already chosen the best response.0using your graph, y=f(x2) will give you the points 2,1 3,0 5,1 6,2
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