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anonymous

  • 4 years ago

how to graph y=f(x)+2 with this graph http://mathgraphs.com/plg5e/plg5emg01d01001.pdf

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  1. phi
    • 4 years ago
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    add 2 to every y value

  2. phi
    • 4 years ago
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    you get the same curve, but slid up 2

  3. anonymous
    • 4 years ago
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    so it would be 2=f(x)+2?

  4. phi
    • 4 years ago
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    they want you to graph y= f(x)+2 that means put dots on the graph at certain points. For example, you put a dot at x= 0 y= -1+2=1 that is 2 up from where the original dot is. then connect the dots

  5. anonymous
    • 4 years ago
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    i see what your saying. but do i use the points given to me or do i choose my own?

  6. phi
    • 4 years ago
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    the instructions say use the graph of f. So you have to use f(x) that means find where the dot is for x=0 (it is at y=-1), add 2 to the y value, and plot it. that is what y= f(x)+2 means. Do it for every x where f(x) has a dot

  7. anonymous
    • 4 years ago
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    okay i see. thank you very much

  8. anonymous
    • 4 years ago
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    x is always constant correct

  9. phi
    • 4 years ago
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    you do not change the x, just the y value.

  10. anonymous
    • 4 years ago
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    okay. im doing y=-f(x) using the same graph so with (0,1) x=0 y=-(-1) ?

  11. anonymous
    • 4 years ago
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    correction *with (0,-1)

  12. phi
    • 4 years ago
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    OK, that's right. you should get a graph that slopes down

  13. anonymous
    • 4 years ago
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    would it not be the same as the original though

  14. phi
    • 4 years ago
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    how can it be the same when you are changing it? plot it and see.

  15. anonymous
    • 4 years ago
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    the points come out on the same line as the first equation (y=f(x)+2)

  16. phi
    • 4 years ago
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    what points did you get? here are the first two pair: original new 0,-1 0,1 1, 0 1,0

  17. anonymous
    • 4 years ago
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    i got the same thing also. i guess i am just confusing myself

  18. phi
    • 4 years ago
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    what did you get for the rest of the points?

  19. anonymous
    • 4 years ago
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    (3,-1),(4,-2) i get it now

  20. anonymous
    • 4 years ago
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    thank you

  21. phi
    • 4 years ago
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    |dw:1328657273507:dw|

  22. anonymous
    • 4 years ago
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    now with the same graph how would y=f(x-2) i understand with (0,-1) x=2+(0)=2 but how would y= work out?

  23. phi
    • 4 years ago
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    y= f(x-2) is short-hand for pick x, for example x=2, now find the y value of f(x-2)= f(0) which is -1 (using the original function). so your point is (2,-1) for x=3, find the y-value of f(3-2)= f(1) = 0, so your next pair is (3,0) and so on. Notice that you can not find values for x=0 or x=1 because you do not know what f(-2) or f(-1) is. But you can find numbers for x=6. The whole graph is shifted to the right 2 spaces.

  24. anonymous
    • 4 years ago
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    so if i have (3,4) , y=f(x-2) then say x=3 , and to find y i would substitute the x. y=3-2=1so my answer would be (3,1)

  25. phi
    • 4 years ago
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    This is not right: y=3-2 what you want is y= f(3-2) that means y= f(1). y=f(1) means look at your graph and at x=1 what is the graph's y value? In your graph it is 0. so the answer is (3,0)

  26. anonymous
    • 4 years ago
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    i don't really get it. in my precall book for point (0,-1) , y=f(x-2) x=0 y=f(0-2)....y=f(-2) (0,-2) ^^i feel this is incorrect

  27. phi
    • 4 years ago
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    You must not be reading my posts very closely. See up above. But you are doing it correctly. You do not have any point to plot at x=0. No problem. Keep going until you get an x that works, and then keep going....

  28. phi
    • 4 years ago
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    btw f(-2) is NOT-2, it is undefined. your point is (0, ???). Try x=2, which is the first x that will work.

  29. anonymous
    • 4 years ago
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    okay il review everything over. oh okay . thank you again

  30. phi
    • 4 years ago
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    using your graph, y=f(x-2) will give you the points 2,-1 3,0 5,1 6,2

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