how to graph y=f(x)+2
with this graph http://mathgraphs.com/plg5e/plg5emg01d01001.pdf

- anonymous

how to graph y=f(x)+2
with this graph http://mathgraphs.com/plg5e/plg5emg01d01001.pdf

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- phi

add 2 to every y value

- phi

you get the same curve, but slid up 2

- anonymous

so it would be 2=f(x)+2?

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## More answers

- phi

they want you to graph y= f(x)+2
that means put dots on the graph at certain points.
For example, you put a dot at x= 0 y= -1+2=1
that is 2 up from where the original dot is.
then connect the dots

- anonymous

i see what your saying. but do i use the points given to me or do i choose my own?

- phi

the instructions say use the graph of f. So you have to use f(x)
that means find where the dot is for x=0 (it is at y=-1), add 2 to the y value, and plot it.
that is what y= f(x)+2 means.
Do it for every x where f(x) has a dot

- anonymous

okay i see. thank you very much

- anonymous

x is always constant correct

- phi

you do not change the x, just the y value.

- anonymous

okay. im doing y=-f(x) using the same graph
so with (0,1)
x=0
y=-(-1) ?

- anonymous

correction *with (0,-1)

- phi

OK, that's right.
you should get a graph that slopes down

- anonymous

would it not be the same as the original though

- phi

how can it be the same when you are changing it? plot it and see.

- anonymous

the points come out on the same line as the first equation (y=f(x)+2)

- phi

what points did you get?
here are the first two pair:
original new
0,-1 0,1
1, 0 1,0

- anonymous

i got the same thing also. i guess i am just confusing myself

- phi

what did you get for the rest of the points?

- anonymous

(3,-1),(4,-2)
i get it now

- anonymous

thank you

- phi

|dw:1328657273507:dw|

- anonymous

now with the same graph how would y=f(x-2)
i understand with (0,-1)
x=2+(0)=2
but how would y= work out?

- phi

y= f(x-2) is short-hand for pick x, for example x=2, now find the y value of f(x-2)= f(0) which is -1 (using the original function). so your point is
(2,-1)
for x=3, find the y-value of f(3-2)= f(1) = 0, so your next pair is
(3,0)
and so on.
Notice that you can not find values for x=0 or x=1 because you do not know what f(-2) or f(-1) is. But you can find numbers for x=6.
The whole graph is shifted to the right 2 spaces.

- anonymous

so if i have (3,4) , y=f(x-2) then say x=3 , and to find y i would substitute the x. y=3-2=1so my answer would be (3,1)

- phi

This is not right: y=3-2 what you want is
y= f(3-2)
that means y= f(1). y=f(1) means look at your graph and at x=1 what is the graph's y value? In your graph it is 0. so the answer is (3,0)

- anonymous

i don't really get it. in my precall book for point (0,-1) , y=f(x-2)
x=0
y=f(0-2)....y=f(-2)
(0,-2)
^^i feel this is incorrect

- phi

You must not be reading my posts very closely. See up above.
But you are doing it correctly. You do not have any point to plot at x=0. No problem. Keep going until you get an x that works, and then keep going....

- phi

btw f(-2) is NOT-2, it is undefined. your point is (0, ???). Try x=2, which is the first x that will work.

- anonymous

okay il review everything over. oh okay . thank you again

- phi

using your graph,
y=f(x-2)
will give you the points
2,-1
3,0
5,1
6,2

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