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anonymous

  • 4 years ago

lim x- >infinity of : ((2x-5)^5) / (7x^2+2x-3)(x^3-6x) ??? common factor, or just distribute??

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  1. anonymous
    • 4 years ago
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    no need to distribute...although that will work. Determine the highest degree in the numerator and the highest degree in the denominator.

  2. anonymous
    • 4 years ago
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    Note that they are both 5

  3. anonymous
    • 4 years ago
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    therefore the limit will be the coefficients of the leading terms.

  4. anonymous
    • 4 years ago
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    2^5/7 or 32/7

  5. anonymous
    • 4 years ago
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    you are only concerned with the leading term. leading term of the numerator is 32x^5 leading term of the denominator is 7x^5 Therefore the limit is the coefficient 32/7.

  6. anonymous
    • 4 years ago
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    ok let me try... Correct!!! thanks men!!>

  7. anonymous
    • 4 years ago
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    sure.

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