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anonymous
 4 years ago
solving systems of Equations by Elimination method:
Tickets for a movie cost $5 for adults and $2 for students. One afternoon 21 tickets were sold and the receipts totled $72. How many of each type of ticket was sold?
a) write a system of equations.
b) solve by using the elimination method.
HELP!!!!!!
anonymous
 4 years ago
solving systems of Equations by Elimination method: Tickets for a movie cost $5 for adults and $2 for students. One afternoon 21 tickets were sold and the receipts totled $72. How many of each type of ticket was sold? a) write a system of equations. b) solve by using the elimination method. HELP!!!!!!

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saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1Wanna learn how to do this?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1Let's suppose the: Adult tickets = x Child ticket = y To find the total tickets sold we will add them. (same as when u have to find the total of something, u add them) So here too we will add them, x + y = Total tickets, therefore, x + y = 21.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay got that so far.

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1Now for the second equation, (let's say one pastry costs about $5. And u want 8 of them, so it means you will write as, (#of pastries * cost of one pastry) 5(8) for the total amount). So here we have total amount for tickets sold. We will write as, (# of adult tickets *cost of one ticket) + (#of child tickets * cost of one ticket) = Total cost.

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1So we have, 5x + 2y = 72

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1Finally two equations, x + y = 21 5x + 2y = 72

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay i got the system of equation, but how do you solve it by using the elimination method can you tech me that?

saifoo.khan
 4 years ago
Best ResponseYou've already chosen the best response.1I am sure those will help!
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