anonymous
  • anonymous
derivative 4^x+6 could you explain in simple terms how to do this in steps, I know its ln, but just stuck in a rut
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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precal
  • precal
are you trying to take the derivative of 4^x + 6?
anonymous
  • anonymous
yes
lgbasallote
  • lgbasallote
is x + 6 in the exponent?

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anonymous
  • anonymous
no sorry x^4 then +6
anonymous
  • anonymous
|dw:1328660528124:dw|
UnkleRhaukus
  • UnkleRhaukus
\[{d(x^4+6)\over dx}\] \[{d(x^4)\over dx}+{d(6)\over dx}=4x^3+0\]
anonymous
  • anonymous
i mean 4^x + 6 i apologize again
anonymous
  • anonymous
This is referred to as the power rule..multiply the coefficient by the exponent and then subtract one from the exponent.
lgbasallote
  • lgbasallote
oh. okay let y = 4^x + 6 lny = xln4 + ln6 1/y(dy/dx) = ln4 cross multiply.... dy/dx = yln4 substitute... dy/dx = (4^x + 6) ln4 i don't know if that can be simplified further but i think that's simplified already
anonymous
  • anonymous
|dw:1328660678342:dw|
y2o2
  • y2o2
2 ln(2)*4^x
anonymous
  • anonymous
y202 gave the same answer in a different form....both are right.
anonymous
  • anonymous
ok thank you guys! my text book is terrible over this section, they show the limits only and thats what im not looking for hah,
anonymous
  • anonymous
so ln(a)*a^x is the format
anonymous
  • anonymous
yes, I usually write it a^xlna

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