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anonymous

  • 4 years ago

derivative 4^x+6 could you explain in simple terms how to do this in steps, I know its ln, but just stuck in a rut

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  1. precal
    • 4 years ago
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    are you trying to take the derivative of 4^x + 6?

  2. anonymous
    • 4 years ago
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    yes

  3. lgbasallote
    • 4 years ago
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    is x + 6 in the exponent?

  4. anonymous
    • 4 years ago
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    no sorry x^4 then +6

  5. anonymous
    • 4 years ago
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    |dw:1328660528124:dw|

  6. UnkleRhaukus
    • 4 years ago
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    \[{d(x^4+6)\over dx}\] \[{d(x^4)\over dx}+{d(6)\over dx}=4x^3+0\]

  7. anonymous
    • 4 years ago
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    i mean 4^x + 6 i apologize again

  8. anonymous
    • 4 years ago
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    This is referred to as the power rule..multiply the coefficient by the exponent and then subtract one from the exponent.

  9. lgbasallote
    • 4 years ago
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    oh. okay let y = 4^x + 6 lny = xln4 + ln6 1/y(dy/dx) = ln4 cross multiply.... dy/dx = yln4 substitute... dy/dx = (4^x + 6) ln4 i don't know if that can be simplified further but i think that's simplified already

  10. anonymous
    • 4 years ago
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    |dw:1328660678342:dw|

  11. y2o2
    • 4 years ago
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    2 ln(2)*4^x

  12. anonymous
    • 4 years ago
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    y202 gave the same answer in a different form....both are right.

  13. anonymous
    • 4 years ago
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    ok thank you guys! my text book is terrible over this section, they show the limits only and thats what im not looking for hah,

  14. anonymous
    • 4 years ago
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    so ln(a)*a^x is the format

  15. anonymous
    • 4 years ago
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    yes, I usually write it a^xlna

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