anonymous 4 years ago There are many ropes holding up a hot air balloon floating away before the balloon race. One of these ropes is fixed to the ground at 45 degrees angle. Another is fixed at a 30 degree angle. If the Hot air balloon is fixed at 21feet off the ground, what is the distance between the ground directly underneath the ballloon and the second rope rounded to the nearest humdreth of a foot?

1. anonymous

Is it 134.511?

2. anonymous

21/sin(30) = 134.511

3. Mertsj

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4. Mertsj

$\tan 30=\frac{21}{d}$

5. Mertsj

$d=\frac{21}{\tan 30}=36.37 ft$

6. anonymous

Thank you

7. Mertsj

yw