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anonymous

  • 4 years ago

PROBLEM SOLVING USING SYSTEMS OF EQUATIONS There are 28 coins that are all nickles and dimes. The value is $2.05. How many nickles are there and how many dimes?

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  1. lgbasallote
    • 4 years ago
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    let x = no. of nickels y = no. of dimes x + y = 28 5(cents)x + 10(cents)y = 205 cents multiply the first equation by -10 -10x -10y = -280 5x + 10y = 205 -5x = -75 x = 15 There are 15 nickels and 13 dimes.

  2. precal
    • 4 years ago
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    you can also use x+y=28 .05x+.10y=2.05

  3. anonymous
    • 4 years ago
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    N + D = 28 5N + 10D = 205 -5(N + D = 28) 5N + 10D = 205 -5N - 5D = 140 5N + 10D = 205 -------------------------- 5D = 65 D = 13 N = 15 There were 13 dimes and 15 nickels

  4. anonymous
    • 4 years ago
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    thankyou so much!

  5. anonymous
    • 4 years ago
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    no problem

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