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anonymous

  • 4 years ago

A force of 2N will stretch a rubber band 0.02m. Assuming that Hooke's Law applies, answer the following: How far will a 1600N force stretch the rubber band? How much work does it take to stretch the rubber band this far?

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  1. anonymous
    • 4 years ago
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    hey lol i can help with this one

  2. anonymous
    • 4 years ago
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    haha... sup man!

  3. anonymous
    • 4 years ago
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    so if you set 1600n = (2n/.002m)x and solve you get x = 16

  4. anonymous
    • 4 years ago
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    wow Benburn you are so smart ;) you should help me on mine

  5. NotTim
    • 4 years ago
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    F1=2N x1=0.02m Look for "K" with the first variables F2= 1600N x2=? K= The one you figured out previously. That solves the first one. W=f*d F=1600N d =Whatever was from the prev. question (as x) W=?

  6. NotTim
    • 4 years ago
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    AWWW

  7. anonymous
    • 4 years ago
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    these things are blowing my mind... I thought I had a clue, guess not.

  8. anonymous
    • 4 years ago
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    so to write an integral that uses that w = \[\int\limits_{0}^{13}100x dx\]

  9. anonymous
    • 4 years ago
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    Ben, do I start with the F= -kx?

  10. anonymous
    • 4 years ago
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    sorry its 0->16

  11. anonymous
    • 4 years ago
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    ya ok let me start over. so you know you put in 2N to make it streach .02m right? so you can solve for k by 2N = k (.02m)-->k=2/.02-->100

  12. anonymous
    • 4 years ago
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    yep.. so K=100

  13. anonymous
    • 4 years ago
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    so next, if you know it takes 1600N how long is it? the equation is 1600N = (100)(x) and if you solve for x, x = 1600/100---> x = 16m

  14. anonymous
    • 4 years ago
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    make sense so far?

  15. anonymous
    • 4 years ago
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    Yep, so 16 is delta

  16. anonymous
    • 4 years ago
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    so

  17. anonymous
    • 4 years ago
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    100x^2/2

  18. anonymous
    • 4 years ago
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    ok so work is an integral of force. the equation will be 100x because that is k*distance... w = int_{0}^{16}100x dx

  19. anonymous
    • 4 years ago
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    \[\int\limits_{0}^{16}100x dx\] ---> [50x^2] from 16 to 0

  20. anonymous
    • 4 years ago
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    I got 12800

  21. anonymous
    • 4 years ago
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    Joules

  22. anonymous
    • 4 years ago
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    ya is that right?

  23. anonymous
    • 4 years ago
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    yep.

  24. anonymous
    • 4 years ago
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    You are a great tutor, ben!

  25. anonymous
    • 4 years ago
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    lol np. does it make sense?

  26. anonymous
    • 4 years ago
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    Yeah man it did.. Thanks alot. I'm going to try #3 now.

  27. anonymous
    • 4 years ago
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    haha ok sounds good send me a message on FB if you want me to try and answer on here

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