A force of 2N will stretch a rubber band 0.02m. Assuming that Hooke's Law applies, answer the following: How far will a 1600N force stretch the rubber band? How much work does it take to stretch the rubber band this far?

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A force of 2N will stretch a rubber band 0.02m. Assuming that Hooke's Law applies, answer the following: How far will a 1600N force stretch the rubber band? How much work does it take to stretch the rubber band this far?

Mathematics
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hey lol i can help with this one
haha... sup man!
so if you set 1600n = (2n/.002m)x and solve you get x = 16

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wow Benburn you are so smart ;) you should help me on mine
F1=2N x1=0.02m Look for "K" with the first variables F2= 1600N x2=? K= The one you figured out previously. That solves the first one. W=f*d F=1600N d =Whatever was from the prev. question (as x) W=?
AWWW
these things are blowing my mind... I thought I had a clue, guess not.
so to write an integral that uses that w = \[\int\limits_{0}^{13}100x dx\]
Ben, do I start with the F= -kx?
sorry its 0->16
ya ok let me start over. so you know you put in 2N to make it streach .02m right? so you can solve for k by 2N = k (.02m)-->k=2/.02-->100
yep.. so K=100
so next, if you know it takes 1600N how long is it? the equation is 1600N = (100)(x) and if you solve for x, x = 1600/100---> x = 16m
make sense so far?
Yep, so 16 is delta
so
100x^2/2
ok so work is an integral of force. the equation will be 100x because that is k*distance... w = int_{0}^{16}100x dx
\[\int\limits_{0}^{16}100x dx\] ---> [50x^2] from 16 to 0
I got 12800
Joules
ya is that right?
yep.
You are a great tutor, ben!
lol np. does it make sense?
Yeah man it did.. Thanks alot. I'm going to try #3 now.
haha ok sounds good send me a message on FB if you want me to try and answer on here

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