anonymous
  • anonymous
A force of 2N will stretch a rubber band 0.02m. Assuming that Hooke's Law applies, answer the following: How far will a 1600N force stretch the rubber band? How much work does it take to stretch the rubber band this far?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
hey lol i can help with this one
anonymous
  • anonymous
haha... sup man!
anonymous
  • anonymous
so if you set 1600n = (2n/.002m)x and solve you get x = 16

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More answers

anonymous
  • anonymous
wow Benburn you are so smart ;) you should help me on mine
NotTim
  • NotTim
F1=2N x1=0.02m Look for "K" with the first variables F2= 1600N x2=? K= The one you figured out previously. That solves the first one. W=f*d F=1600N d =Whatever was from the prev. question (as x) W=?
NotTim
  • NotTim
AWWW
anonymous
  • anonymous
these things are blowing my mind... I thought I had a clue, guess not.
anonymous
  • anonymous
so to write an integral that uses that w = \[\int\limits_{0}^{13}100x dx\]
anonymous
  • anonymous
Ben, do I start with the F= -kx?
anonymous
  • anonymous
sorry its 0->16
anonymous
  • anonymous
ya ok let me start over. so you know you put in 2N to make it streach .02m right? so you can solve for k by 2N = k (.02m)-->k=2/.02-->100
anonymous
  • anonymous
yep.. so K=100
anonymous
  • anonymous
so next, if you know it takes 1600N how long is it? the equation is 1600N = (100)(x) and if you solve for x, x = 1600/100---> x = 16m
anonymous
  • anonymous
make sense so far?
anonymous
  • anonymous
Yep, so 16 is delta
anonymous
  • anonymous
so
anonymous
  • anonymous
100x^2/2
anonymous
  • anonymous
ok so work is an integral of force. the equation will be 100x because that is k*distance... w = int_{0}^{16}100x dx
anonymous
  • anonymous
\[\int\limits_{0}^{16}100x dx\] ---> [50x^2] from 16 to 0
anonymous
  • anonymous
I got 12800
anonymous
  • anonymous
Joules
anonymous
  • anonymous
ya is that right?
anonymous
  • anonymous
yep.
anonymous
  • anonymous
You are a great tutor, ben!
anonymous
  • anonymous
lol np. does it make sense?
anonymous
  • anonymous
Yeah man it did.. Thanks alot. I'm going to try #3 now.
anonymous
  • anonymous
haha ok sounds good send me a message on FB if you want me to try and answer on here

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