## anonymous 4 years ago A force of 2N will stretch a rubber band 0.02m. Assuming that Hooke's Law applies, answer the following: How far will a 1600N force stretch the rubber band? How much work does it take to stretch the rubber band this far?

1. anonymous

hey lol i can help with this one

2. anonymous

haha... sup man!

3. anonymous

so if you set 1600n = (2n/.002m)x and solve you get x = 16

4. anonymous

wow Benburn you are so smart ;) you should help me on mine

5. NotTim

F1=2N x1=0.02m Look for "K" with the first variables F2= 1600N x2=? K= The one you figured out previously. That solves the first one. W=f*d F=1600N d =Whatever was from the prev. question (as x) W=?

6. NotTim

AWWW

7. anonymous

these things are blowing my mind... I thought I had a clue, guess not.

8. anonymous

so to write an integral that uses that w = $\int\limits_{0}^{13}100x dx$

9. anonymous

Ben, do I start with the F= -kx?

10. anonymous

sorry its 0->16

11. anonymous

ya ok let me start over. so you know you put in 2N to make it streach .02m right? so you can solve for k by 2N = k (.02m)-->k=2/.02-->100

12. anonymous

yep.. so K=100

13. anonymous

so next, if you know it takes 1600N how long is it? the equation is 1600N = (100)(x) and if you solve for x, x = 1600/100---> x = 16m

14. anonymous

make sense so far?

15. anonymous

Yep, so 16 is delta

16. anonymous

so

17. anonymous

100x^2/2

18. anonymous

ok so work is an integral of force. the equation will be 100x because that is k*distance... w = int_{0}^{16}100x dx

19. anonymous

$\int\limits_{0}^{16}100x dx$ ---> [50x^2] from 16 to 0

20. anonymous

I got 12800

21. anonymous

Joules

22. anonymous

ya is that right?

23. anonymous

yep.

24. anonymous

You are a great tutor, ben!

25. anonymous

lol np. does it make sense?

26. anonymous

Yeah man it did.. Thanks alot. I'm going to try #3 now.

27. anonymous

haha ok sounds good send me a message on FB if you want me to try and answer on here