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liizzyliizz

  • 4 years ago

if f(x)= ae^kx and f'(x)/f(x)= -5/2 then k= Help lol (Relearning calculus and basic rules :P )

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  1. bahrom7893
    • 4 years ago
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    find the derivative of f(x): f'(x) = a*e^(kx)*k (Chain rule)

  2. bahrom7893
    • 4 years ago
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    f'(x) = a*k*e^(kx) f'(x)/f(x) = -5/2, so a*k*e^(kx)/[a*e^(kx)] = -5/2

  3. anonymous
    • 4 years ago
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    \[f(x)=ae ^{kx}\]\[f'(x)=ake ^{kx}\]reaplce:\[\frac{ake ^{kx}}{ae ^{kx}}=-\frac{5}{2}\]\[k=-\frac{5}{2}\]

  4. bahrom7893
    • 4 years ago
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    a*e^(kx) on top and bottom cancel out, so u're left with k = -5/2

  5. anonymous
    • 4 years ago
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    remember: \[f(x)=e ^{u} \]\[f \prime(x)=e ^{u}u \prime\]

  6. liizzyliizz
    • 4 years ago
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    O.o This is so simple lol I am embarrassed I got this wrong now :(

  7. anonymous
    • 4 years ago
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    dont forget, click good answer :D jeje

  8. liizzyliizz
    • 4 years ago
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    lol there you go :) Thanks for the help.

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