pokemon23
  • pokemon23
factor the binomial
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
pokemon23
  • pokemon23
|dw:1328666307791:dw|
Akshay_Budhkar
  • Akshay_Budhkar
\[a^2-b^2=(a+b)(a-b)\] here a= c , b= 10 So\[c^2-10^2= (c+10)(c-10)\]
pokemon23
  • pokemon23
I knew it omg -_-

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More answers

Akshay_Budhkar
  • Akshay_Budhkar
LOL
Akshay_Budhkar
  • Akshay_Budhkar
so am i supposed to just correct it?
pokemon23
  • pokemon23
yes
pokemon23
  • pokemon23
let me post up my second question should we continue here or make another post
Akshay_Budhkar
  • Akshay_Budhkar
ur choice ur wish, doesnt matter to me :P if u want medals u can post another question
pokemon23
  • pokemon23
Not in it for the medals in it for math ;D
Akshay_Budhkar
  • Akshay_Budhkar
so go ahead here. i never solve for medals i solve for satisfaction, i love helping lol
pokemon23
  • pokemon23
|dw:1328666654526:dw|
Akshay_Budhkar
  • Akshay_Budhkar
Nope u messed up with the a and b here.. u interchanged them so u r getting a negative answer
pokemon23
  • pokemon23
so its (c-12) (c-12)
Akshay_Budhkar
  • Akshay_Budhkar
No!
Akshay_Budhkar
  • Akshay_Budhkar
\[144 - c^2 = 12^2-c^2 = (12-c)(12+c)\] note your a in the formula here is 12 ad not c and b is c
pokemon23
  • pokemon23
-_-
Akshay_Budhkar
  • Akshay_Budhkar
silly errors are gonna bring you down buddy
pokemon23
  • pokemon23
don't jinx me
Akshay_Budhkar
  • Akshay_Budhkar
O_o am i?
Akshay_Budhkar
  • Akshay_Budhkar
u got more stufF?
pokemon23
  • pokemon23
yes
Akshay_Budhkar
  • Akshay_Budhkar
ok go ahead
pokemon23
  • pokemon23
|dw:1328667147093:dw|
pokemon23
  • pokemon23
|dw:1328667200620:dw|
Akshay_Budhkar
  • Akshay_Budhkar
silly error^
Akshay_Budhkar
  • Akshay_Budhkar
\[{1 \over 64} = ({1 \over8})^2\]
pokemon23
  • pokemon23
-_- your making me fail
pokemon23
  • pokemon23
wait where does the w^2 go
pokemon23
  • pokemon23
|dw:1328667483269:dw|
Akshay_Budhkar
  • Akshay_Budhkar
\[w^2- ({1 \over 8})^2= [1-{1 \over 8}][1+{1 \over 8}]\]
Akshay_Budhkar
  • Akshay_Budhkar
oppsie i meant\[(w- { 1 \over 8} )(w+ {1 \over 8} )\]
pokemon23
  • pokemon23
darn silly mistakes
Akshay_Budhkar
  • Akshay_Budhkar
concentrate..
pokemon23
  • pokemon23
good point
pokemon23
  • pokemon23
Represent the area of a square whose side is represented by: 2/3x
pokemon23
  • pokemon23
|dw:1328667760624:dw|
Akshay_Budhkar
  • Akshay_Budhkar
|dw:1328678598703:dw|
pokemon23
  • pokemon23
dam -_-
Akshay_Budhkar
  • Akshay_Budhkar
u need rest buddy :P
pokemon23
  • pokemon23
|dw:1328667836337:dw|
Akshay_Budhkar
  • Akshay_Budhkar
yes
pokemon23
  • pokemon23
haven't slept for two days
Akshay_Budhkar
  • Akshay_Budhkar
high five same here :P .. well its 3 for me :P
Akshay_Budhkar
  • Akshay_Budhkar
today will be the 4th probably
pokemon23
  • pokemon23
omg your insane
Akshay_Budhkar
  • Akshay_Budhkar
lol
pokemon23
  • pokemon23
I will would probably got knock out
Akshay_Budhkar
  • Akshay_Budhkar
lol it is tough when u got problems to battle :P Especially those related to love :P Anyways lets get back to studies
Akshay_Budhkar
  • Akshay_Budhkar
u got more stuff?
pokemon23
  • pokemon23
yes
Akshay_Budhkar
  • Akshay_Budhkar
ok
pokemon23
  • pokemon23
write the expression in factored form
pokemon23
  • pokemon23
|dw:1328668229216:dw|
pokemon23
  • pokemon23
two more questions will be asking write the expression in factored form
Akshay_Budhkar
  • Akshay_Budhkar
|dw:1328679073491:dw|
pokemon23
  • pokemon23
yes :d ONE QUESTION RIGHT
Akshay_Budhkar
  • Akshay_Budhkar
lol
pokemon23
  • pokemon23
|dw:1328668342605:dw|
Akshay_Budhkar
  • Akshay_Budhkar
yup
pokemon23
  • pokemon23
yes second question right :D
pokemon23
  • pokemon23
|dw:1328668602826:dw|
pokemon23
  • pokemon23
i know im wrong
pokemon23
  • pokemon23
i left the second p
Akshay_Budhkar
  • Akshay_Budhkar
yes u got ur mistake
pokemon23
  • pokemon23
|dw:1328668849284:dw|
Akshay_Budhkar
  • Akshay_Budhkar
???
Akshay_Budhkar
  • Akshay_Budhkar
brb
pokemon23
  • pokemon23
|dw:1328668973454:dw|
Akshay_Budhkar
  • Akshay_Budhkar
\[p + prt = p(1 +rt)\]
pokemon23
  • pokemon23
i was correct :D
pokemon23
  • pokemon23
thanks for the help ;D
Akshay_Budhkar
  • Akshay_Budhkar
Yw

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