- pokemon23

factor the binomial

- chestercat

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- pokemon23

|dw:1328666307791:dw|

- Akshay_Budhkar

\[a^2-b^2=(a+b)(a-b)\] here a= c , b= 10 So\[c^2-10^2= (c+10)(c-10)\]

- pokemon23

I knew it omg -_-

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## More answers

- Akshay_Budhkar

LOL

- Akshay_Budhkar

so am i supposed to just correct it?

- pokemon23

yes

- pokemon23

let me post up my second question should we continue here or make another post

- Akshay_Budhkar

ur choice ur wish, doesnt matter to me :P if u want medals u can post another question

- pokemon23

Not in it for the medals in it for math ;D

- Akshay_Budhkar

so go ahead here. i never solve for medals i solve for satisfaction, i love helping lol

- pokemon23

|dw:1328666654526:dw|

- Akshay_Budhkar

Nope u messed up with the a and b here.. u interchanged them so u r getting a negative answer

- pokemon23

so its (c-12) (c-12)

- Akshay_Budhkar

No!

- Akshay_Budhkar

\[144 - c^2 = 12^2-c^2 = (12-c)(12+c)\] note your a in the formula here is 12 ad not c and b is c

- pokemon23

-_-

- Akshay_Budhkar

silly errors are gonna bring you down buddy

- pokemon23

don't jinx me

- Akshay_Budhkar

O_o am i?

- Akshay_Budhkar

u got more stufF?

- pokemon23

yes

- Akshay_Budhkar

ok go ahead

- pokemon23

|dw:1328667147093:dw|

- pokemon23

|dw:1328667200620:dw|

- Akshay_Budhkar

silly error^

- Akshay_Budhkar

\[{1 \over 64} = ({1 \over8})^2\]

- pokemon23

-_- your making me fail

- pokemon23

wait where does the w^2 go

- pokemon23

|dw:1328667483269:dw|

- Akshay_Budhkar

\[w^2- ({1 \over 8})^2= [1-{1 \over 8}][1+{1 \over 8}]\]

- Akshay_Budhkar

oppsie i meant\[(w- { 1 \over 8} )(w+ {1 \over 8} )\]

- pokemon23

darn silly mistakes

- Akshay_Budhkar

concentrate..

- pokemon23

good point

- pokemon23

Represent the area of a square whose side is represented by: 2/3x

- pokemon23

|dw:1328667760624:dw|

- Akshay_Budhkar

|dw:1328678598703:dw|

- pokemon23

dam -_-

- Akshay_Budhkar

u need rest buddy :P

- pokemon23

|dw:1328667836337:dw|

- Akshay_Budhkar

yes

- pokemon23

haven't slept for two days

- Akshay_Budhkar

high five same here :P .. well its 3 for me :P

- Akshay_Budhkar

today will be the 4th probably

- pokemon23

omg your insane

- Akshay_Budhkar

lol

- pokemon23

I will would probably got knock out

- Akshay_Budhkar

lol it is tough when u got problems to battle :P Especially those related to love :P Anyways lets get back to studies

- Akshay_Budhkar

u got more stuff?

- pokemon23

yes

- Akshay_Budhkar

ok

- pokemon23

write the expression in factored form

- pokemon23

|dw:1328668229216:dw|

- pokemon23

two more questions will be asking write the expression in factored form

- Akshay_Budhkar

|dw:1328679073491:dw|

- pokemon23

yes :d ONE QUESTION RIGHT

- Akshay_Budhkar

lol

- pokemon23

|dw:1328668342605:dw|

- Akshay_Budhkar

yup

- pokemon23

yes second question right :D

- pokemon23

|dw:1328668602826:dw|

- pokemon23

i know im wrong

- pokemon23

i left the second p

- Akshay_Budhkar

yes u got ur mistake

- pokemon23

|dw:1328668849284:dw|

- Akshay_Budhkar

???

- Akshay_Budhkar

brb

- pokemon23

|dw:1328668973454:dw|

- Akshay_Budhkar

\[p + prt = p(1 +rt)\]

- pokemon23

i was correct :D

- pokemon23

thanks for the help ;D

- Akshay_Budhkar

Yw

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