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pokemon23

  • 4 years ago

factor the binomial

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  1. pokemon23
    • 4 years ago
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    |dw:1328666307791:dw|

  2. Akshay_Budhkar
    • 4 years ago
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    \[a^2-b^2=(a+b)(a-b)\] here a= c , b= 10 So\[c^2-10^2= (c+10)(c-10)\]

  3. pokemon23
    • 4 years ago
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    I knew it omg -_-

  4. Akshay_Budhkar
    • 4 years ago
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    LOL

  5. Akshay_Budhkar
    • 4 years ago
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    so am i supposed to just correct it?

  6. pokemon23
    • 4 years ago
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    yes

  7. pokemon23
    • 4 years ago
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    let me post up my second question should we continue here or make another post

  8. Akshay_Budhkar
    • 4 years ago
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    ur choice ur wish, doesnt matter to me :P if u want medals u can post another question

  9. pokemon23
    • 4 years ago
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    Not in it for the medals in it for math ;D

  10. Akshay_Budhkar
    • 4 years ago
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    so go ahead here. i never solve for medals i solve for satisfaction, i love helping lol

  11. pokemon23
    • 4 years ago
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    |dw:1328666654526:dw|

  12. Akshay_Budhkar
    • 4 years ago
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    Nope u messed up with the a and b here.. u interchanged them so u r getting a negative answer

  13. pokemon23
    • 4 years ago
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    so its (c-12) (c-12)

  14. Akshay_Budhkar
    • 4 years ago
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    No!

  15. Akshay_Budhkar
    • 4 years ago
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    \[144 - c^2 = 12^2-c^2 = (12-c)(12+c)\] note your a in the formula here is 12 ad not c and b is c

  16. pokemon23
    • 4 years ago
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    -_-

  17. Akshay_Budhkar
    • 4 years ago
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    silly errors are gonna bring you down buddy

  18. pokemon23
    • 4 years ago
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    don't jinx me

  19. Akshay_Budhkar
    • 4 years ago
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    O_o am i?

  20. Akshay_Budhkar
    • 4 years ago
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    u got more stufF?

  21. pokemon23
    • 4 years ago
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    yes

  22. Akshay_Budhkar
    • 4 years ago
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    ok go ahead

  23. pokemon23
    • 4 years ago
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    |dw:1328667147093:dw|

  24. pokemon23
    • 4 years ago
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    |dw:1328667200620:dw|

  25. Akshay_Budhkar
    • 4 years ago
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    silly error^

  26. Akshay_Budhkar
    • 4 years ago
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    \[{1 \over 64} = ({1 \over8})^2\]

  27. pokemon23
    • 4 years ago
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    -_- your making me fail

  28. pokemon23
    • 4 years ago
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    wait where does the w^2 go

  29. pokemon23
    • 4 years ago
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    |dw:1328667483269:dw|

  30. Akshay_Budhkar
    • 4 years ago
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    \[w^2- ({1 \over 8})^2= [1-{1 \over 8}][1+{1 \over 8}]\]

  31. Akshay_Budhkar
    • 4 years ago
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    oppsie i meant\[(w- { 1 \over 8} )(w+ {1 \over 8} )\]

  32. pokemon23
    • 4 years ago
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    darn silly mistakes

  33. Akshay_Budhkar
    • 4 years ago
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    concentrate..

  34. pokemon23
    • 4 years ago
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    good point

  35. pokemon23
    • 4 years ago
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    Represent the area of a square whose side is represented by: 2/3x

  36. pokemon23
    • 4 years ago
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    |dw:1328667760624:dw|

  37. Akshay_Budhkar
    • 4 years ago
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    |dw:1328678598703:dw|

  38. pokemon23
    • 4 years ago
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    dam -_-

  39. Akshay_Budhkar
    • 4 years ago
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    u need rest buddy :P

  40. pokemon23
    • 4 years ago
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    |dw:1328667836337:dw|

  41. Akshay_Budhkar
    • 4 years ago
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    yes

  42. pokemon23
    • 4 years ago
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    haven't slept for two days

  43. Akshay_Budhkar
    • 4 years ago
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    high five same here :P .. well its 3 for me :P

  44. Akshay_Budhkar
    • 4 years ago
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    today will be the 4th probably

  45. pokemon23
    • 4 years ago
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    omg your insane

  46. Akshay_Budhkar
    • 4 years ago
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    lol

  47. pokemon23
    • 4 years ago
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    I will would probably got knock out

  48. Akshay_Budhkar
    • 4 years ago
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    lol it is tough when u got problems to battle :P Especially those related to love :P Anyways lets get back to studies

  49. Akshay_Budhkar
    • 4 years ago
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    u got more stuff?

  50. pokemon23
    • 4 years ago
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    yes

  51. Akshay_Budhkar
    • 4 years ago
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    ok

  52. pokemon23
    • 4 years ago
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    write the expression in factored form

  53. pokemon23
    • 4 years ago
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    |dw:1328668229216:dw|

  54. pokemon23
    • 4 years ago
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    two more questions will be asking write the expression in factored form

  55. Akshay_Budhkar
    • 4 years ago
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    |dw:1328679073491:dw|

  56. pokemon23
    • 4 years ago
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    yes :d ONE QUESTION RIGHT

  57. Akshay_Budhkar
    • 4 years ago
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    lol

  58. pokemon23
    • 4 years ago
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    |dw:1328668342605:dw|

  59. Akshay_Budhkar
    • 4 years ago
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    yup

  60. pokemon23
    • 4 years ago
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    yes second question right :D

  61. pokemon23
    • 4 years ago
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    |dw:1328668602826:dw|

  62. pokemon23
    • 4 years ago
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    i know im wrong

  63. pokemon23
    • 4 years ago
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    i left the second p

  64. Akshay_Budhkar
    • 4 years ago
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    yes u got ur mistake

  65. pokemon23
    • 4 years ago
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    |dw:1328668849284:dw|

  66. Akshay_Budhkar
    • 4 years ago
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    ???

  67. Akshay_Budhkar
    • 4 years ago
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    brb

  68. pokemon23
    • 4 years ago
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    |dw:1328668973454:dw|

  69. Akshay_Budhkar
    • 4 years ago
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    \[p + prt = p(1 +rt)\]

  70. pokemon23
    • 4 years ago
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    i was correct :D

  71. pokemon23
    • 4 years ago
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    thanks for the help ;D

  72. Akshay_Budhkar
    • 4 years ago
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    Yw

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