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anonymous
 4 years ago
ok i need help with this word problem
"The sum of the digits of a twodigit number is 8. If 16 is added to the original number, the result is 3 times the original number with its digits reversed. Find the original number."
im pretty sure i have it but i dont know what variable to use for the 2 digit number
anonymous
 4 years ago
ok i need help with this word problem "The sum of the digits of a twodigit number is 8. If 16 is added to the original number, the result is 3 times the original number with its digits reversed. Find the original number." im pretty sure i have it but i dont know what variable to use for the 2 digit number

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Le the digits be x and y. Hence the original number is = 10x + y. Since the digits add up to 8. Hence, x + y = 8 Again adding 16 to the original number we get  10x + y + 16 This number is 3 times of the original number reversed 3(10y + x) Hence, 10x + y + 16 = 3 (10y +x) => 7x  29y = 16 Replacing y = 8  x, we have 7x  29(8  x) = 16 => x = 6, hence y = 8  6 = 2 Hence the original number is 10 * 6 + 2 = 62

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where did the 10 come from?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no no :) that is not 10, I just written "we get ' the number actually is 10x + y + 16

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haha sorry then where did the 10 come from

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.2x is the ten's digit. It's value is 10x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im gonna have more of these coming so get ready haha:)
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