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anonymous
 4 years ago
Heidi and Mike have 51 dimes and nickles. If the value of the coins is $4.10, how many coins of each type were there?
anonymous
 4 years ago
Heidi and Mike have 51 dimes and nickles. If the value of the coins is $4.10, how many coins of each type were there?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0let x = no. of nickles y = no. of dimes x + y = 51 5(cents)x + 10(cents)y = 410 cents multiply the first equation by 10.. 10x  10y = 510 5x + 10y = 410 5x = 100 x = 20 y = 31 There are 20 nickles and 31 dimes

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you for being so specific! :)
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