anonymous
  • anonymous
Heidi and Mike have 51 dimes and nickles. If the value of the coins is $4.10, how many coins of each type were there?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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lgbasallote
  • lgbasallote
let x = no. of nickles y = no. of dimes x + y = 51 5(cents)x + 10(cents)y = 410 cents multiply the first equation by -10.. -10x - 10y = -510 5x + 10y = 410 -5x = -100 x = 20 y = 31 There are 20 nickles and 31 dimes
anonymous
  • anonymous
thank you for being so specific! :)

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