## anonymous 4 years ago f f(x)=3x-8 the f^-1 (y) =??

1. anonymous

suppose you had $3x-8= 50$ and you had to solve for x. what would you do? 1) add 8 2) divide by 3 that is what the inverse does. it is $f^{-1}(y)=\frac{y+8}{3}$

2. anonymous

Thanks!