A community for students.
Here's the question you clicked on:
 0 viewing
liizzyliizz
 4 years ago
The volume of a cube is increasing at a a rate of
300 in^3/min. at the instant when the edge is 20 inches at what rate is the edge changing.
liizzyliizz
 4 years ago
The volume of a cube is increasing at a a rate of 300 in^3/min. at the instant when the edge is 20 inches at what rate is the edge changing.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0edge is \[x = \sqrt[3]{V}\] so \[x'(t)=\frac{1}{3\sqrt[3]{V^2}}\times V'(t)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are told that \[V'(t)=300\] so you get \[x'(t)=\frac{300}{3\sqrt[3]{V^2}}=\frac{100}{\sqrt[3]{V^2}}\] so all you need to finish is to find out what V is when x is 20

liizzyliizz
 4 years ago
Best ResponseYou've already chosen the best response.0Ahh, so for future problems similar to this how would one know to go about this.

liizzyliizz
 4 years ago
Best ResponseYou've already chosen the best response.0I still blame my algebra skills, but that is just me lol

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.1dV/dT = 300 when e = 20 volume of a cube = e^3 dV/dT = 3e^2(de/dt) 300 = 3e^2 (de/dt) de/dt = 300/3e^2 when e =20 de/dt = 300/3(20)^2 de/dt = 1/4 in/min is the answer I came up with.

liizzyliizz
 4 years ago
Best ResponseYou've already chosen the best response.0^ that made a lot more sense lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.