## anonymous 4 years ago Solve by completing the square & quadratic formula: x^2 6x + 17 = 0

1. anonymous

$x^2+6x+17=0$ or $x^2-6x+17=0$??

2. anonymous

Gah, sorry. x^2 + 6x + 17 = 0

3. anonymous

$x^2+6x=-17$ $(x+3)^2=-17+9$ $(x+3)^2=-8$ now either you are done because you can't take the root of a negative number, or else you are allowing complex solutions. which is it?

4. anonymous

I'm assuming the second option- some of the answers are things like: $x = 3i \sqrt{2}$

5. anonymous

actually if you are using complext numbers it would be $x=2\sqrt{2}i$ or $x=-2\sqrt{2}i$

6. anonymous

...What is it with me today...? But, yes, we've been doing complex numbers.