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anonymous
 4 years ago
more calculus help
anonymous
 4 years ago
more calculus help

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?}(1)/(xln(x ^{4}))\]

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1that 1/x is buggin me as a u sub.. but it's prolly integration by parts

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0start with \[\frac{1}{x\ln(x^4)}=\frac{1}{4x\ln(x)}\] then it should be easy

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1Ha I think i got this one!

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1u = ln(x^4) du = 4/x simple u sub!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0good. because i am clueless???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0pull the 1/4 outside of the integral get \[\frac{1}{4}\int \frac{dx}{x\ln(x)}\] then make \[u=\ln(x),du=\frac{1}{x}dx\] and you are home free

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1well yea pretty much the same thing as satellite did

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0don't forget the properties of the log!

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1lol my method works too though :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes it will work and you will see that if \[u=\ln(x^4)\] then \[du=\frac{4}{x}dx\] but that is telling you that \[\ln(x^4)=4\ln(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would the fianl answer be 1/4ln (ln(x))+c?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0btw if you notice you will get a different answer from wolfram and if you like i can explain why

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0here is what wolfram writes if you just type it in. you get \[\frac{1}{4}\ln(\ln(x^4))+c\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but \[\ln(\ln(x^4))=\ln(4\ln(x))=\ln(4)+\ln(\ln(x))\] and \[\ln(4) \] is a constant. so answers are the same, since the constant is just a constant, like the +C out at the end

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oo ok that is simple enough thanks again
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