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precal
 4 years ago
what is the derivative of
y=(tanx)/(1+secx)
precal
 4 years ago
what is the derivative of y=(tanx)/(1+secx)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hint:multiply top/bottom by secx

precal
 4 years ago
Best ResponseYou've already chosen the best response.0I got y' = (secx)/(1+secx) but wolfram alpha does not have that as a solution

precal
 4 years ago
Best ResponseYou've already chosen the best response.0I can't multiply by secx for the top and bottom I have to use quotient rule

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sec(x) (tan^2(x)+sec^2(x)+sec(x))

precal
 4 years ago
Best ResponseYou've already chosen the best response.0No Jinnie I don't think that is correct

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahaha i forgot it was a division problem

y2o2
 4 years ago
Best ResponseYou've already chosen the best response.0\[{\sec(x) \tan(x)^2\over(\sec(x)+1)^2}+{\sin(x)^2\over(\cos(x)^2}+{\cos(x))+1\over(\sec(x)+1)}\]

precal
 4 years ago
Best ResponseYou've already chosen the best response.0y2o2 what are you using to find y prime?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it does work at walfarm, check this out: http://www.wolframalpha.com/input/?i=d%2F+dx+%28sinx%2Fcosx%29%2F%281%2Bsecx%29&cdf=1

precal
 4 years ago
Best ResponseYou've already chosen the best response.0no iHelp that is not correct

precal
 4 years ago
Best ResponseYou've already chosen the best response.0I used a pythagorean identity for tan^2t

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0tanx/(secx+1)=sinx/cosx+1, let u=cosx+1, du=sinxdx, so integral of 1/u, which is lnu , subisitute u back in...

precal
 4 years ago
Best ResponseYou've already chosen the best response.0this is not an integration problem, I am just looking for the derivative

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow, srry misread the problem  my bad

precal
 4 years ago
Best ResponseYou've already chosen the best response.0its ok, you were on a roll there

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just make sure, derivative of product is first*deri of second minus second*deri of first right?>

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y'=sec^2x(1+secx)tan^2xsecx , is that right ?

precal
 4 years ago
Best ResponseYou've already chosen the best response.0that is the product rule, I need to use the quotient rule.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nvm. miss read problem again.. wow fml...

precal
 4 years ago
Best ResponseYou've already chosen the best response.0I use lodehihidelo over lolo

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0last try lol... y'=(sec^2x(1+secx)tan(xsecxtanx))/(1+secx)^2,,

precal
 4 years ago
Best ResponseYou've already chosen the best response.0yes I distributed tanx to secxtanx and got secxtan^2x then I used the pyth. identity to get rid of tan^2x

precal
 4 years ago
Best ResponseYou've already chosen the best response.0I think I am right. I do believe wolfram alpha is not able to put all variations of a solution down. Programming issue.

precal
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks to everyone Good night

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0=) solution page is not always right.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes you are correct...i also get dy/dx = sec/(1+sec) you can change it in terms of cos > dy/dx = 1/(1+cos) and this is one of the forms given on wolframalpha

precal
 4 years ago
Best ResponseYou've already chosen the best response.0when do you suggest I change it to cosx? In the beginning before I take the derivative or at the end?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it doesn't really matter...it depends on the function, in this case if you changed it before it would have made taking the derivative simpler

precal
 4 years ago
Best ResponseYou've already chosen the best response.0ok I will go back and redo the problem. Thanks for your help :)
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