i need help solve each equation. check your solution
y-6/y=5
5/3p+2/3=5+p/2p

- anonymous

i need help solve each equation. check your solution
y-6/y=5
5/3p+2/3=5+p/2p

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- anonymous

rational equation

- radar

|dw:1328670179691:dw|
Is that the first one?

- anonymous

yess

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

i really dont understand how to do this

- radar

O.K Multiply thru by y getting y-6 = 5y
5y-y=-6
4y=-6
y=-6/4 = -3/2 = -1 1/2

- radar

Did you follow that with understanding?

- anonymous

imm sorry u wrote the equation wrong

- anonymous

|dw:1330225757998:dw|

- radar

OH I see. Now multiply the equation thru by y getting \[y ^{2}-6=5y\]With me so far?

- anonymous

nopee

- radar

You are going to multiply all terms by y in order to eliminate the denominator.
\[y \times y=y ^{2}\] Did you follow on the first term?

- anonymous

mhmmm

- radar

|dw:1328670943075:dw|

- radar

Do you see how the second term becomes a -6?

- anonymous

no how

- radar

and finally 5*y= 5y
Do you know how to multiply? What grade are you in?

- anonymous

yes and in 10th grade

- anonymous

ohhh i get it nowww

- radar

|dw:1328671370618:dw|

- anonymous

soo wats the next step

- radar

|dw:1328671430551:dw|
What part of this multiplication you do not understand?

- anonymous

nooooo i understandd

- anonymous

whats the next step

- radar

So we are now back to \[y ^{2}-6=5y\]
Subtracting 5y from both sides we get\[y ^{2}-5y-6=5y-5y=0\]This is a quadratic equation that can be factored and easily solved.\[y ^{2}-5y-6=0\]
(y-6)(y+1)=0
y=6
y=-1
those are the two answers. Your problem say to check your work

- anonymous

okm theres the next onee

- anonymous

so would you multiply 3

- anonymous

|dw:1330227284130:dw|

- radar

Checking y -6/y=5
6 -6/6=5
6-1=5
5=5 that checks.
-1-6/-1=5
-1+6=5
5=5 that checks too.

- anonymous

yesss so for the next problem would you multiply by 3p?

- radar

Let me look that over

- radar

First lets put all terms containing p on the left.
5/(3p)-(5+p)/(2p)=-2/3 This was done by subtracting 2/3 from both sides.

- anonymous

ok

- radar

|dw:1328672483382:dw|

- radar

Multiply all terms by 6p eliminate the denominator\[10-15-3p =-4p\]Please double check my work here as I go and let the dogs in.

- anonymous

where did 15 come from?

- anonymous

its -8 not -4

- radar

The 15 came from multiplying (6p/2p)-(5+p)|dw:1328673206774:dw|

- anonymous

ohhh ok

- radar

what is -8 ??
Multiply (-2/3)(6p)=-4p

- anonymous

ohh ok

- radar

Let us continue:
combining similar terms we now have: -5 - 3p =-4p
adding 5 and adding 4p to both sides gives us
p=5 that is the answer that we must check out. You feel up to it?

- anonymous

yesss

- radar

|dw:1328673792581:dw| I will use your drawing to check out the answer

- radar

5/(3*5) + 2/3 = (5+5)/2*5
5/15 +2/3 = 10/10
1/3 +2/3 = 1
1=1 5 is the correct answer.

- radar

Agree?

- anonymous

ohh ok next problem

- radar

Post the problem in the ask a question side.

- anonymous

|dw:1330229287420:dw|

- radar

That way it gets more exposure and that is the preferred policy of open study.

- anonymous

yess agreed

- radar

I believe I can answer that one, but post it on the ask a question and I will meet you there.

- anonymous

ok thnk u

Looking for something else?

Not the answer you are looking for? Search for more explanations.