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anonymous

  • 4 years ago

i need help solve each equation. check your solution y-6/y=5 5/3p+2/3=5+p/2p

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  1. anonymous
    • 4 years ago
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    rational equation

  2. radar
    • 4 years ago
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    |dw:1328670179691:dw| Is that the first one?

  3. anonymous
    • 4 years ago
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    yess

  4. anonymous
    • 4 years ago
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    i really dont understand how to do this

  5. radar
    • 4 years ago
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    O.K Multiply thru by y getting y-6 = 5y 5y-y=-6 4y=-6 y=-6/4 = -3/2 = -1 1/2

  6. radar
    • 4 years ago
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    Did you follow that with understanding?

  7. anonymous
    • 4 years ago
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    imm sorry u wrote the equation wrong

  8. anonymous
    • 4 years ago
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    |dw:1330225757998:dw|

  9. radar
    • 4 years ago
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    OH I see. Now multiply the equation thru by y getting \[y ^{2}-6=5y\]With me so far?

  10. anonymous
    • 4 years ago
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    nopee

  11. radar
    • 4 years ago
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    You are going to multiply all terms by y in order to eliminate the denominator. \[y \times y=y ^{2}\] Did you follow on the first term?

  12. anonymous
    • 4 years ago
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    mhmmm

  13. radar
    • 4 years ago
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    |dw:1328670943075:dw|

  14. radar
    • 4 years ago
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    Do you see how the second term becomes a -6?

  15. anonymous
    • 4 years ago
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    no how

  16. radar
    • 4 years ago
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    and finally 5*y= 5y Do you know how to multiply? What grade are you in?

  17. anonymous
    • 4 years ago
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    yes and in 10th grade

  18. anonymous
    • 4 years ago
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    ohhh i get it nowww

  19. radar
    • 4 years ago
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    |dw:1328671370618:dw|

  20. anonymous
    • 4 years ago
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    soo wats the next step

  21. radar
    • 4 years ago
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    |dw:1328671430551:dw| What part of this multiplication you do not understand?

  22. anonymous
    • 4 years ago
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    nooooo i understandd

  23. anonymous
    • 4 years ago
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    whats the next step

  24. radar
    • 4 years ago
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    So we are now back to \[y ^{2}-6=5y\] Subtracting 5y from both sides we get\[y ^{2}-5y-6=5y-5y=0\]This is a quadratic equation that can be factored and easily solved.\[y ^{2}-5y-6=0\] (y-6)(y+1)=0 y=6 y=-1 those are the two answers. Your problem say to check your work

  25. anonymous
    • 4 years ago
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    okm theres the next onee

  26. anonymous
    • 4 years ago
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    so would you multiply 3

  27. anonymous
    • 4 years ago
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    |dw:1330227284130:dw|

  28. radar
    • 4 years ago
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    Checking y -6/y=5 6 -6/6=5 6-1=5 5=5 that checks. -1-6/-1=5 -1+6=5 5=5 that checks too.

  29. anonymous
    • 4 years ago
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    yesss so for the next problem would you multiply by 3p?

  30. radar
    • 4 years ago
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    Let me look that over

  31. radar
    • 4 years ago
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    First lets put all terms containing p on the left. 5/(3p)-(5+p)/(2p)=-2/3 This was done by subtracting 2/3 from both sides.

  32. anonymous
    • 4 years ago
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    ok

  33. radar
    • 4 years ago
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    |dw:1328672483382:dw|

  34. radar
    • 4 years ago
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    Multiply all terms by 6p eliminate the denominator\[10-15-3p =-4p\]Please double check my work here as I go and let the dogs in.

  35. anonymous
    • 4 years ago
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    where did 15 come from?

  36. anonymous
    • 4 years ago
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    its -8 not -4

  37. radar
    • 4 years ago
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    The 15 came from multiplying (6p/2p)-(5+p)|dw:1328673206774:dw|

  38. anonymous
    • 4 years ago
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    ohhh ok

  39. radar
    • 4 years ago
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    what is -8 ?? Multiply (-2/3)(6p)=-4p

  40. anonymous
    • 4 years ago
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    ohh ok

  41. radar
    • 4 years ago
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    Let us continue: combining similar terms we now have: -5 - 3p =-4p adding 5 and adding 4p to both sides gives us p=5 that is the answer that we must check out. You feel up to it?

  42. anonymous
    • 4 years ago
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    yesss

  43. radar
    • 4 years ago
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    |dw:1328673792581:dw| I will use your drawing to check out the answer

  44. radar
    • 4 years ago
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    5/(3*5) + 2/3 = (5+5)/2*5 5/15 +2/3 = 10/10 1/3 +2/3 = 1 1=1 5 is the correct answer.

  45. radar
    • 4 years ago
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    Agree?

  46. anonymous
    • 4 years ago
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    ohh ok next problem

  47. radar
    • 4 years ago
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    Post the problem in the ask a question side.

  48. anonymous
    • 4 years ago
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    |dw:1330229287420:dw|

  49. radar
    • 4 years ago
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    That way it gets more exposure and that is the preferred policy of open study.

  50. anonymous
    • 4 years ago
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    yess agreed

  51. radar
    • 4 years ago
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    I believe I can answer that one, but post it on the ask a question and I will meet you there.

  52. anonymous
    • 4 years ago
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    ok thnk u

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