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liizzyliizz

  • 4 years ago

given the curve 4x^2+2xy-xy^3=3 find the values of dy/dx at the point (1,-1)

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  1. bahrom7893
    • 4 years ago
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    implicit differentiation

  2. anonymous
    • 4 years ago
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    \[4x^2+2xy-xy^3=3\] \[8x+2xy'+2y-y^3-3xy^2y'=0\] replace x and y by the numbers you know and solve for \[y'\]

  3. bahrom7893
    • 4 years ago
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    8x + 2 * (x * dy/dx + y) - (x * 3y^2 * dy/dx + y^3) = 0

  4. bahrom7893
    • 4 years ago
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    Ughh I keep crashing for some reason... now just do whatever satellite said.

  5. liizzyliizz
    • 4 years ago
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    So would it be 7? I am not sure I probably messed something up. I will double check.

  6. anonymous
    • 4 years ago
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    now it is arithmetic i can try it, maybe

  7. anonymous
    • 4 years ago
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    \[8x+2xy'+2y-y^3-3xy^2y'=0\] \[8+2y'-2-1-3y'=0\]

  8. anonymous
    • 4 years ago
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    i replaced each x by 1 and each y by -1, but i am not guarenteeing my answer

  9. anonymous
    • 4 years ago
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    this gives \[5-y'=0\] or \[y'=5\] again, i would not bet my lunch money on it, but it looks right

  10. liizzyliizz
    • 4 years ago
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    ohh i added the one in stead of subtracting :l ugh the dangers of negative signs lol

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