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anonymous

  • 4 years ago

how do i find the volume of the remaining solid? ill draw a picture

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  1. anonymous
    • 4 years ago
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    |dw:1328670911000:dw|

  2. anonymous
    • 4 years ago
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    I don't understand, but if it's a cylindre with other cylindre inside, it's: R^2*h-r^2*h=(R^2-r^2)h Where R=6, r=2, h=5 Then: (6^2-2^2)*5=(36-4)*5=32*5=160

  3. Mertsj
    • 4 years ago
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    The volume of the big cylinder is pi (3)^2(5)=45 pi Volume of the little cylinder is pi (1)^2(5)= 5 pi Now subtract and get 40 pi and that is the remaining volume after you bore that hole in the middle.

  4. dumbcow
    • 4 years ago
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    i think the 6 and 2 refer to the diameters not the radius --> volume = 40pi

  5. Mertsj
    • 4 years ago
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    I think so too. That's why I used 3 for the radius of the big cylinder and 1 for the radius of the small cylinder.

  6. anonymous
    • 4 years ago
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    Yes, you're right I have to look closer next time.

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