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anonymous

  • 4 years ago

If a, b are the solutions of (((15)/(t+6))+((t+4)/(3)))=4 compute the sum of a+b plz show work and i would be very happy if someone were to help me/explain this problem

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  1. anonymous
    • 4 years ago
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    first let me see if i can read what is says

  2. anonymous
    • 4 years ago
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    \[\frac{15}{t+6}+\frac{t+4}{3}=4\]??

  3. anonymous
    • 4 years ago
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    yuppers

  4. anonymous
    • 4 years ago
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    the sum of a+b for tht equation

  5. anonymous
    • 4 years ago
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    well i don't think there is a shortcut. i think you have to find the solutions and add them

  6. anonymous
    • 4 years ago
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    or at least write the quadratic equation out

  7. anonymous
    • 4 years ago
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    oh damn i made a mistake!

  8. anonymous
    • 4 years ago
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    \[\frac{45+(t+4)(t+6)}{3(t+6)}=4\]

  9. anonymous
    • 4 years ago
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    \[45+(t+4)(t+6)=12(t+6)\] \[t^2+10t+69=12t+72\] \[t^2-2t-3=0\] and finally \[(t-3)(t+1)=0\] solutions area 3 and -1

  10. anonymous
    • 4 years ago
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    if you add them you get 2

  11. anonymous
    • 4 years ago
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    it is also true that the sum of the solutions to \[ax^2+bx+c=0\] is \[-\frac{b}{a}\]so we did not actually have to solve once we got to \[x^2-2x-3=0\]

  12. anonymous
    • 4 years ago
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    thank much man appreciate it hope some good karma comes back to u one day ^^

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