anonymous
  • anonymous
A teacher has a set of 12 problems to use on a math exam. The teacher makes different versions of the exam by putting 10 questions on each exam. How many different exams can the teacher make? A.12! / 11! B. 66 C. 132 D. 12!
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
I think it's B, 66 12!/(10!*2!)=12*11/2!=12*11/2=6*11=66
anonymous
  • anonymous
http://mathworld.wolfram.com/Combination.html He combines 10 questions of a set of 12.
anonymous
  • anonymous
thanks

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anonymous
  • anonymous
You're welcome.

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