x^2+12y+y^2+3x-12=0 find the center and radius od the circle

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x^2+12y+y^2+3x-12=0 find the center and radius od the circle

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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do you know how to complete the square? because you want it to look like \[(x-h)^2+(y+k)^2=r^2\] so you can read off you answer
what mertsj said
i completed the square. i got (x+1.5)^2+(y+6)^2=50.25. i don't know if that's right

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yup
so my rudius is 7.10 and center (-1.5,-6)?
yes, if that square root is right (it looks right)

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