At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

do you have any idea how I got the formula u'(x)=f'(g(x))g'(x) in the last problem?

no

ok

so see if you can apply that to find the derivative of\[\large F(x)=f(x^3)\]

3x^2

not quite, it's
3x^2f'(x^3)
by the chain rule

oh ok

3(4)(6)

72

yes!

now try to come up with an expression for G'(x)
remember the chain rule

3f(x)^2f'(x)

nice!
now you've got those quantities as well, so what's G'(a) ?

24

alot of the people whom i seek help from would just belittle me

it has discourage me from seeking help face to face

new things are always tricky, I'm just glad I could help
good luck, and don't forget the chain rule!

alright thanks. i am done for the day. take care