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Mathhelp346
 4 years ago
Use graphing to solve:
a. x+2=6
b.x+2>6
Mathhelp346
 4 years ago
Use graphing to solve: a. x+2=6 b.x+2>6

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campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1graph the y = x + 2 and graph y = 6 dw:1328675607779:dw find the points of intersection (4, 6) and (8, 6) so read off the graph... when is x + 2 . 6.... when x > 4 and 8<x

Mathhelp346
 4 years ago
Best ResponseYou've already chosen the best response.0but how do you know where the arrow goes?

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1pick a point.... say (1, 1) sub x= 1 into x + 2>6 then  1+2 > 6 T or F... its false so (1,1) isn't in the region... choose a point test it and see if its in or out of the region...

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1look at the graph... when is the graph of x +2 above the line y = 6..... and describe the x values.... then graph is above the line y = 6 when x > 4 and also when x < 8

Mathhelp346
 4 years ago
Best ResponseYou've already chosen the best response.0but how do you know how far the arrow will stretch? why (4,6) and (8,6)?

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1well the domain of x + 2 is all real x.... an inequality can have infinite solutions.

Mathhelp346
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but why (4,6)? why not (6,4) or something?

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.1x + 2= 6 is really asking where the lines y=x +2 and y=6 intersect... that was the 1st task in your question, solve graphically.... sou graoh both and read off the points intersections... then its is asking.. when is x + 2 greater then 6... or really when is it greater than the line y = 6
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