A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Solve using quadratic formula:
x(x2)  3(2x5) = 2
...Let's just say I'm just as bad with this formula as I am with fractions.
anonymous
 4 years ago
Solve using quadratic formula: x(x2)  3(2x5) = 2 ...Let's just say I'm just as bad with this formula as I am with fractions.

This Question is Closed

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0well expand and simplify 1st x^2  2x  6x + 15 = 2 so x^2 8x + 13 = 8 GQF \[(b \pm \sqrt{b^2  4ac})/2a\] a = 1, b = 8 c = 13 ... substitute and simplify. You should get \[(8 \pm \sqrt{10})/2\]

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0simplifyed equation should be x^2  6x + 13 = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The equation is simplified to \[x^28x+5=0\] a=1 b=8 c=5 Quadrstic formula \[x=\frac{b \pm \sqrt{b^24ac}}{2a}\]

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0actuually c = 13... not 8

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Wait... Wouldn't that be: x^2  8x + 13 = 0 ?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.