## anonymous 4 years ago Solve using quadratic formula: x(x-2) - 3(2x-5) = 2 ...Let's just say I'm just as bad with this formula as I am with fractions.

1. campbell_st

well expand and simplify 1st x^2 - 2x - 6x + 15 = 2 so x^2 -8x + 13 = 8 GQF $(-b \pm \sqrt{b^2 - 4ac})/2a$ a = 1, b = -8 c = 13 ... substitute and simplify. You should get $(-8 \pm \sqrt{10})/2$

2. campbell_st

simplifyed equation should be x^2 - 6x + 13 = 0

3. anonymous

The equation is simplified to $x^2-8x+5=0$ a=1 b=-8 c=5 Quadrstic formula $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

4. campbell_st

actuually c = 13... not 8

5. anonymous

Wait... Wouldn't that be: x^2 - 8x + 13 = 0 ?