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anonymous

  • 4 years ago

Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the balloon at time t = 25 seconds?: V =?

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  1. anonymous
    • 4 years ago
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    How fast is the volume changing after 25 seconds? I think this a derivative so dV/dt

  2. bahrom7893
    • 4 years ago
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    V' = 2/(sqrt(t))

  3. campbell_st
    • 4 years ago
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    V= 4t^1/2 dV/dt = 2t^-1/2

  4. campbell_st
    • 4 years ago
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    then sum 25 for t

  5. campbell_st
    • 4 years ago
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    oops sub 25 for t

  6. campbell_st
    • 4 years ago
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    looks like +-2/5 cm3/sec

  7. TuringTest
    • 4 years ago
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    who asked about rate of change?

  8. bahrom7893
    • 4 years ago
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    He did

  9. anonymous
    • 4 years ago
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    me

  10. bahrom7893
    • 4 years ago
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    Btw when t = 25, the volume is 20

  11. TuringTest
    • 4 years ago
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    that's all it asks as far as I can see 'What is the volume of the balloon at time t = 25 seconds?'

  12. bahrom7893
    • 4 years ago
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    next post below that

  13. TuringTest
    • 4 years ago
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    ah, I'm blind sometimes!

  14. anonymous
    • 4 years ago
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    ok thanks

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