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anonymous
 4 years ago
Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3.
What is the volume of the balloon at time t = 25 seconds?: V =?
anonymous
 4 years ago
Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the balloon at time t = 25 seconds?: V =?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How fast is the volume changing after 25 seconds? I think this a derivative so dV/dt

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.2V= 4t^1/2 dV/dt = 2t^1/2

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.2looks like +2/5 cm3/sec

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0who asked about rate of change?

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1Btw when t = 25, the volume is 20

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0that's all it asks as far as I can see 'What is the volume of the balloon at time t = 25 seconds?'

bahrom7893
 4 years ago
Best ResponseYou've already chosen the best response.1next post below that

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0ah, I'm blind sometimes!
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