Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the balloon at time t = 25 seconds?: V =?

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Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the balloon at time t = 25 seconds?: V =?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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How fast is the volume changing after 25 seconds? I think this a derivative so dV/dt
V' = 2/(sqrt(t))
V= 4t^1/2 dV/dt = 2t^-1/2

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Other answers:

then sum 25 for t
oops sub 25 for t
looks like +-2/5 cm3/sec
who asked about rate of change?
He did
me
Btw when t = 25, the volume is 20
that's all it asks as far as I can see 'What is the volume of the balloon at time t = 25 seconds?'
next post below that
ah, I'm blind sometimes!
ok thanks

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