anonymous
  • anonymous
Suppose a spherical balloon grows in such a way that after t seconds, its volume is V = 4 sqrt(t) cm3. What is the volume of the balloon at time t = 25 seconds?: V =?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
How fast is the volume changing after 25 seconds? I think this a derivative so dV/dt
bahrom7893
  • bahrom7893
V' = 2/(sqrt(t))
campbell_st
  • campbell_st
V= 4t^1/2 dV/dt = 2t^-1/2

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campbell_st
  • campbell_st
then sum 25 for t
campbell_st
  • campbell_st
oops sub 25 for t
campbell_st
  • campbell_st
looks like +-2/5 cm3/sec
TuringTest
  • TuringTest
who asked about rate of change?
bahrom7893
  • bahrom7893
He did
anonymous
  • anonymous
me
bahrom7893
  • bahrom7893
Btw when t = 25, the volume is 20
TuringTest
  • TuringTest
that's all it asks as far as I can see 'What is the volume of the balloon at time t = 25 seconds?'
bahrom7893
  • bahrom7893
next post below that
TuringTest
  • TuringTest
ah, I'm blind sometimes!
anonymous
  • anonymous
ok thanks

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