anonymous
  • anonymous
Complete the square and use quadratic formula: x^2 - 2x - 1 = 0 I got to: x^2 - 2x = 1 (x + 2)^2 = +/-√2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
bahrom7893
  • bahrom7893
x^2 - 2x - 1 + 2 = 2 (x-1)^2 = 2
anonymous
  • anonymous
Darn. (x+2)^2 = 2 x + 2 = +/-√2
bahrom7893
  • bahrom7893
why would they want to complete the square? it's not helping..

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

bahrom7893
  • bahrom7893
x-1 = +-sqrt(2) x = -sqrt(2) + 1 x = sqrt(2)+1
bahrom7893
  • bahrom7893
well actually it was helping
bahrom7893
  • bahrom7893
That's by completing the square
bahrom7893
  • bahrom7893
x^2 - 2x - 1 = 0 D = (-2)^2 - 4*1*(-1)=4+4 = 8
bahrom7893
  • bahrom7893
x1 = (2 - sqrt(8))/2 = 1 - sqrt(2) x2 = (2 + sqrt(8))/2 = 1 + sqrt(2)
bahrom7893
  • bahrom7893
come on now, make me level 59!
bahrom7893
  • bahrom7893
yay lol!
anonymous
  • anonymous
Thank you. :D
bahrom7893
  • bahrom7893
tnx
bahrom7893
  • bahrom7893
and np

Looking for something else?

Not the answer you are looking for? Search for more explanations.