anonymous
  • anonymous
find the area of the segment of a circle. radius 6 cm and angle 120 degrees
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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campbell_st
  • campbell_st
well its 2 problems... in 1 |dw:1328677721761:dw| find the area of the triangle with sides 6cm and angle 120 A = 1/2 absinC find the area of the sector... A = 120/360 x pi x 6^2 the segment will be Area of sector - Area of Triangle
anonymous
  • anonymous
Pi(r)^2 would be the full circle. Then divide that by 3 to get 1/3 of it or 120 degrees. pi(6)^2=113.097 -> /3=37.69 campbel are you sure you want to use a triangle? maybe I dont understand the question but this is my thought...
anonymous
  • anonymous
you can also note that 120 degrees is one third of a the circle, therefore it will be 1/3 the area of the entire circle A = pi*r^2 = pi*6^2 = 36 pi since it's A/3 then. A/3=36pi/3=12pi

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anonymous
  • anonymous
what if you are only supposed to use geometry? this is for a geometry class. they have not used sin yet
anonymous
  • anonymous
both ways work just fine
anonymous
  • anonymous
geometry method is described by me and loophole
campbell_st
  • campbell_st
then you can't find the area of a segment without using the sector - triangle
anonymous
  • anonymous
how do you find the area of a triangle without knowing base or height?
campbell_st
  • campbell_st
loophole and matt... are only finding the area of a sector... and not a segment...
campbell_st
  • campbell_st
use trigonometry... A = 1/2 x 6 x 6 x sin(120)
anonymous
  • anonymous
a sector is just a divided circle.
anonymous
  • anonymous
campbell's right. wasn't thinking. if it IS the segment they ask for, then yes you have to subtract the area of the the triangle
anonymous
  • anonymous
ohh, okay you're right a segment is different.
anonymous
  • anonymous
yest that is what I am asking

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