anonymous
  • anonymous
f(x)= (6x)−1/2 + 5 f ' (x) =?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
6x^-1/2
anonymous
  • anonymous
(-1/2)(6)(x^(-3/2)
lgbasallote
  • lgbasallote
-1/2(6x^-3/2) -1/[2 sqrt of (6x)^3]

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campbell_st
  • campbell_st
well f'(x) = -3x^-3/2 \[f '(x) = -3/\sqrt{x^3}\]
anonymous
  • anonymous
i've already tried -3x^-3/2 and -3/sqrt3 but i have not tried -1/2 sqrt of 6x^3
lgbasallote
  • lgbasallote
nahhh. that was wrong :)) 6 should be in the numerator
anonymous
  • anonymous
somehow the answer is -1/2x*sqrt6x..... dont know how
campbell_st
  • campbell_st
just look at my solution....
anonymous
  • anonymous
idk how though
campbell_st
  • campbell_st
you have -1/2 * 6 = -3 x^(-3/2) = 1/x^3/2 so its 3 * 1/x^3/2

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