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anonymous
 4 years ago
f(x)= (6x)−1/2 + 5
f ' (x) =?
anonymous
 4 years ago
f(x)= (6x)−1/2 + 5 f ' (x) =?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.01/2(6x^3/2) 1/[2 sqrt of (6x)^3]

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0well f'(x) = 3x^3/2 \[f '(x) = 3/\sqrt{x^3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i've already tried 3x^3/2 and 3/sqrt3 but i have not tried 1/2 sqrt of 6x^3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nahhh. that was wrong :)) 6 should be in the numerator

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0somehow the answer is 1/2x*sqrt6x..... dont know how

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0just look at my solution....

campbell_st
 4 years ago
Best ResponseYou've already chosen the best response.0you have 1/2 * 6 = 3 x^(3/2) = 1/x^3/2 so its 3 * 1/x^3/2
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