anonymous
  • anonymous
graph y = x^3 – 4x^2 + 6. Describe what you see. How is what you observe here different from what you observed in part A?
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
PART A is :A.Graph y = x^3 – 2x^2 + 6. Describe what you see.
anonymous
  • anonymous
yal still there ?
anonymous
  • anonymous
in first equation you can set x = 0 to get y = 6

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anonymous
  • anonymous
but you can't sub 6 to get the same answer ...
anonymous
  • anonymous
the answer would be : 6 = = x^3 – 4x^2 + 6 0=x^3-4x^2 either x = zero or .. x=4
anonymous
  • anonymous
no the same matter of equation 2 in part A

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