anonymous
  • anonymous
which of the following does not have tetrrahedral str. a)BH4^-1 b)BH3 C)NH4^+1 d)H2O
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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AravindG
  • AravindG
bh3
AravindG
  • AravindG
it has no lone pairs
anonymous
  • anonymous
well H2O is also not tetrahedral str. its pyramidal

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AravindG
  • AravindG
ys sorry i didnt see that
AravindG
  • AravindG
k now help meeeeeeeee
anonymous
  • anonymous
heena is right
anonymous
  • anonymous
yar its a ques of medical exam and they have given ans BF3 i dont get y only this ans y not H2o as i was solving ques. paper last night can any one give me gud reason of this?
anonymous
  • anonymous
If you are talking in terms of geometry then water has tetrahedral GEOMETRY (It is sp3 hybridized). But two vertices of the tetrahedron make it a V shape but its gemetry is still tetrahedral. Now BH3 or more aptly BF3 is sp2 hybrizidez meaning its shape and geometry are trigonal planar. So i would say it is only BH3. (BH4- is sp3).
anonymous
  • anonymous
but yar its not fair na then ans BH4^-1 will also have different geometry if i agree u
anonymous
  • anonymous
If you did not get the difference between geometry and shape then: Geometry: It is the arrangement of its orbitals(ORBITALS NOT ATOMS) Shape: It is the arrangement of its atoms. Consider H2O: It is sp3 hybrid meaning its orbitals are along the corners of a tetrahedron meaning its gemoetry is tetrahedral but two of those vertices are lone pars and only two vertices are filled with atoms So its shape is V shape.
anonymous
  • anonymous
BH4- is sp3. Tetrahedral geometry.
anonymous
  • anonymous
ok listen boron had 5 electron rit now it made four bonds with hydrogen now it had left 2 electron as well including -ve charge den how it will have sp3?
AravindG
  • AravindG
yaar return in 5 min therre k?
anonymous
  • anonymous
Of course it has sp3. it has three valence electrons + 4 from Hydrogen + 1 from negative charge=8 electrons: Clearly sp3.
anonymous
  • anonymous
yup fine take ur own time arvind i m nt having anyprob u need more than half an hour u can
AravindG
  • AravindG
i told u to return!!!
anonymous
  • anonymous
but yar in exam how we come to know that whether we have to see hybridisation or str. as there are so many exceptuions wwhose hybridisation says diff. and their str. from diff. its better to leave this ques to prevent -ve marking??
anonymous
  • anonymous
but yar in exam how we come to know that whether we have to see hybridisation or str. as there are so many exceptions whose hybridisation says diff. and their str. form diff. its better to leave this ques to prevent -ve marking??
AravindG
  • AravindG
hmm i suggest u draw xtra bubbles
AravindG
  • AravindG
:P
anonymous
  • anonymous
Nah do you know the method to calculate hybridization?
anonymous
  • anonymous
yup all shortcuts even that u told dat i also know :P
anonymous
  • anonymous
When did i tell you shortcuts?
anonymous
  • anonymous
the way u said to calculate hybridisation above :P
anonymous
  • anonymous
i did it before when i was learning but due to some str. excption i started using other method by which ans didnt comes wrong :)
anonymous
  • anonymous
Which method?
anonymous
  • anonymous
mine one or urs?? which one u want to know? well there is several formula but i m lil lazy to learn that so i prefer to understand like nwadays i m using str. one example like H2O noe see here oxygen makes 2sigma bond and have lone pair now max. distance u can place is 180degree but due to presence of lonepair it bends and gives u pyramidal str.
anonymous
  • anonymous
mostly in exam instead of asking hybridisation they as k how many sigma bonds and pie bonds are present
anonymous
  • anonymous
See here's another shorcut. First find central atom. Calculate number of surrounding atoms + no of lone pairs. Like in H2O. It is 2 surrounding atoms and two lone pairs so you get 4. 2 means sp, 3 means sp2, 4 means sp3, 5 means sp3d and so on.
anonymous
  • anonymous
i know this as i said i was using it only for hybridisation but dey dont ask, they ask str. mostly in a indirect way v.clever they are :P
anonymous
  • anonymous
I've not seen any exceptions for this one.... indirect way? if you know hybridization and lone pairs you can always deduce strucute. What indirect way?
anonymous
  • anonymous
but u know for hybridisation we calculate sigma bond and lone pair ok fine for such i m giving u example in which hybridistion match but str. dont as one example u see like H2O
anonymous
  • anonymous
hold on lemme bring notebook as i dont remember
anonymous
  • anonymous
Yeah so geometry is sp3 and two lone pairs so you remove two atoms out of a tetra hedron you get a V no... There's nothing so tricky about it anyway.....
anonymous
  • anonymous
hey tertrahedral is a diff str i guess and in result u get pyramidal dat is tricky itself.. u r now usethrough from it so u knw
anonymous
  • anonymous
H2O is not pyrimidal.
anonymous
  • anonymous
like str. of H2O2
anonymous
  • anonymous
but its not tetrahedral too if u draw the str.
anonymous
  • anonymous
say hybrisdisation of H2O2 and its str. too
anonymous
  • anonymous
H2O2 will be open book structure here both Oxygen will be sp3. You can;t decide hybiridization as there are 2 ceentral atoms.
anonymous
  • anonymous
hey sp3 nw here concepts fail na abu str say??
anonymous
  • anonymous
dat was i m saying dat for hybridisation its good but smtimes they ask abu str den u can be in trouble
anonymous
  • anonymous
There are two sp3 oxygen no so you can't say the structure directly. There is no trouble, Here it does not give a satisfactory explanation as there are two central atoms if there is only one central atom then you can use hybrid concept. Even here if you see the two oxygens are sp3 and must be tetrahedral . If you draw both oxygens as sp3 ,then you still get the structure,
anonymous
  • anonymous
ok just ans me hybridisation of SO2 ok
anonymous
  • anonymous
its sp2.
anonymous
  • anonymous
ok by this u say its triagonal rit
anonymous
  • anonymous
Gemoetry trigonal planar, Shape : V shape.
anonymous
  • anonymous
Don;t forget the lone pair out of a triangle you remove one corner you get a V rite?
anonymous
  • anonymous
dat i m saying geometry says triagonal but in real its v shape :) that i m tring to say u
anonymous
  • anonymous
u got it or still have objection??
anonymous
  • anonymous
I already told you the answer.
anonymous
  • anonymous
And explained it too there is one lone pair in a trianle you remove one vertex you get some V shape rite?
anonymous
  • anonymous
i know u urself ans. that hope u get wat i m trying to say sir...
anonymous
  • anonymous
ok fine in exam they dont as the reason they only ask which will have v shape as all options will have sp3 hybridised then this concepts fails na then u have to come to see str. by using mind :P
anonymous
  • anonymous
dat the thing i m saying hybridisatin not always gives accurate ans in case of str.
anonymous
  • anonymous
NO you're not getting what i'm trying to tell. See First you find geometry by hybridization . Then You find number of lone pairs. In that geometry you put lone pairs at the corners. Then excluding those corners whatever you get is the shape of the molecule.
anonymous
  • anonymous
yes that i m sayin that ultimate u have to see the lone pairs i mean by sp3 wat comes in ur mind that it is tetrahedral rit but when u look at lone pair u get that the str. have some chnges due to presence of it
anonymous
  • anonymous
Isn;t that kinda easy where is the problem in that?
anonymous
  • anonymous
uhmm.. well i have to leave urgently had to take lunch den have to study gtg cya tc
anonymous
  • anonymous
@shankvee i agree wid u as u said abu that sp3 is tetrahedral but distorted due to presence of lone pair but wat i said is also not wrong in sense as m having exam on ma mind :) thnx for the info otherwise i always think always hybridisation is not right

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