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anonymous

  • 4 years ago

I am trying to prove E(kin)=(3/2)RT (T in kelvin) in order to prove pV=nRT (so i cant use that equation) I have proved E(kin)=(1/2)mv^2

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  1. y2o2
    • 4 years ago
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    So, do you know that pV = NKT ?!

  2. anonymous
    • 4 years ago
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    no that is what i am trying to prove

  3. anonymous
    • 4 years ago
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    or is N mole and K=R here or is it something else? Where R is molar gas constant = 8.314472 m2 kg s-2 K-1 mol-1

  4. y2o2
    • 4 years ago
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    Actually \[E_{K.E} = {3 \over 2} KT \ \ Not \ \ {3\over2}RT\] where K is Boltzmann constant , not the Universal gas constant. and K = R/A where A is Avogadro's number.

  5. y2o2
    • 4 years ago
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    http://en.wikipedia.org/wiki/Ideal_gas_law

  6. Mani_Jha
    • 4 years ago
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    Do u know that PV=\[mnc ^{2}/3\]? From here u get K.E=3(PV/n)/2 per molecule. Combining boyle's and charle's law and avogadro's law, u will get \[P1V1/nT1 = CONSTANT\] for any gas, which is called R. Thus PV=nRT. Put this value and u will get K.E=3RT/2 per molecule

  7. anonymous
    • 4 years ago
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    i wanted to prove it without thoose laws like avogadros law since to me it seems like they are based on empirical data and I wanted to prove it theorethically because I like it better :)

  8. anonymous
    • 4 years ago
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    we use Equipartition theorem to get E(k)=3KT/2, and use Boltzmann statistics to prove PV=nRT, and in this way we get Boltzmann Constant quantitatively ,namely K=AR, where A is Avergadro Constant.

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