anonymous
  • anonymous
In the equation of the circle (x-5)^2+(y-5)^2=50,does it touches with the origin?Find the center of the circle?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
>>In the equation of the circle (x-5)^2+(y-5)^2=50,does it touches with the origin? Put x=0 and y=0 and it's satisfies the equation so it does. >>Find the center of the circle? (5,5)
campbell_st
  • campbell_st
Centre (5,5) so draw a right triangle.... and see if the hypotenuse is equal to the radius. |dw:1328696735242:dw| \[r = 5\sqrt{2}\] from the circle equation using Pythagoras 's theorem.. 5^2 + 5^2 = ch^2 ch ^2 = 50... sam as sth
campbell_st
  • campbell_st
tHE hypotenuse is \[h = 5\sqrt{?}\] the same as the radius so the circle touches the origin

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

campbell_st
  • campbell_st
? = 2

Looking for something else?

Not the answer you are looking for? Search for more explanations.