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anonymous
 4 years ago
Suppose f(π/6)=7 and f′(π/6)=−4 ,
and let g(x)=f(x)cosx and h(x)=sinx/f(x)
g'(π/6)=?
h'(π/6)=?
anonymous
 4 years ago
Suppose f(π/6)=7 and f′(π/6)=−4 , and let g(x)=f(x)cosx and h(x)=sinx/f(x) g'(π/6)=? h'(π/6)=?

This Question is Closed

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[g(x)=f(x)\cos (x)\] \[g'(x)=f'(x)\cos (x)f(x)\sin (x)\] \[g'(30)=f'(30)\cos(30)f(30)\sin(30)\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[g'(30)=4(\frac{\sqrt{3}}{2})7(\frac{1}{2})\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[h(x)=\frac{\sin x}{f(x)}\] \[h'(x)=\frac{f(x)\cos x\sin xf'(x)}{[f(x)]^{2}}\ ]\[h'(30)=\frac{f(30)\cos (30)\sin (30)f'(30)}{[f(30]^{2}}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[h'(30)=\frac{f(30)\cos (30)\sin (30)f'(30)}{[f(30)]^{2}}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[h'(30)=\frac{7(\frac{\sqrt{3}}{2}\frac{1}{2}(4)}{7^{2}}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0\[h'(30)=\frac{14\sqrt{3}+2}{49}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0I used 30 instead of pi/6 so I wouldn't have to type all those fractions.
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