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anonymous
 4 years ago
Can someone please check me (to make sure my reasoning is sound, primarily...but always nice to have the algebra looked at as well)?
d/dx [(x2) d/dx (5x4)]
=d/dx [(x2)(4x^3)]
=d/dx [4x^4 + 8x^3]
= 16x^3 + 24x^2
anonymous
 4 years ago
Can someone please check me (to make sure my reasoning is sound, primarily...but always nice to have the algebra looked at as well)? d/dx [(x2) d/dx (5x4)] =d/dx [(x2)(4x^3)] =d/dx [4x^4 + 8x^3] = 16x^3 + 24x^2

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that should read d/dx (5x^4) up top

Kainui
 4 years ago
Best ResponseYou've already chosen the best response.0Looks correct to me. A helpful tool to use is www.wolframalpha.com

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks. When I can put this kind of query into wolframalpha I do, but it didn't like the syntax on this one.

Kainui
 4 years ago
Best ResponseYou've already chosen the best response.0Try breaking it up and just doing one derivative at a time. =)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You're too right, but I wasn't sure it would be ok to do...now I am the wiser, and I thank you.
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