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anonymous

  • 4 years ago

Find the missing numbers in the circles, so that the numbers in the squares are each equal to the sum of the two numbers in the circles on either side. Please see attached.

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  1. anonymous
    • 4 years ago
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  2. ash2326
    • 4 years ago
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    we have 1st...a+b=8 2nd...b+c=9 3rd....a+c=10 subtract 2nd from third, we get a-b=1 a+b=8 add these we get 2a=9 a=4.5 a-b=1 so b=3.5 a+c=10 c=10-a c=10-4.5 c=5.5 a=4.5 b=3.5 c=5.5

  3. anonymous
    • 4 years ago
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    7/2 8 9 9/2 10 11/2

  4. anonymous
    • 4 years ago
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    I don't understand

  5. anonymous
    • 4 years ago
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    Just form the equations and solve as ash posted.

  6. anonymous
    • 4 years ago
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    subtract second from third??????? dont get it

  7. anonymous
    • 4 years ago
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    should I treat them as systems of equations???

  8. anonymous
    • 4 years ago
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    yes that's right Chrissy.

  9. phi
    • 4 years ago
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    This may be useful, if it makes sense to you.

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