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anonymous
 4 years ago
What value must be chosen for a to make tis function continuous at 1? 2x^3+x^2+7x+8/x+1 when x<1 and by x^2+2x+a when 1< or = x
anonymous
 4 years ago
What value must be chosen for a to make tis function continuous at 1? 2x^3+x^2+7x+8/x+1 when x<1 and by x^2+2x+a when 1< or = x

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nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.0lim of the function when x comes to 1 from the left side must be equal to the lim of the function when x comes to 1 from the right side. Make that equality and you'll get value for a...be careful at that first function, you'll get 0/0 if you plug in x=1immediately, so, to avoid that, use a little bit of algebra knowledge and you'll get value for lim

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you give me a step by step way to solve it please?

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.0ok wait a minute

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.0you can write down the first function like this:\[(x+1)(2x^2x+8)/(x+1)=2x^2x+8\] now if you plug in x=1 you'll get: \[2*1+1+8=11\] that's the limit as x approaches 1 from the left side...now if you plug in x=1 into the other function you'll get 3+a....so you must say 11=3+a and a=14

nenadmatematika
 4 years ago
Best ResponseYou've already chosen the best response.0you're welcome :D
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