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anonymous
 4 years ago
An isosceles triangle has base B and height H. Assuming its area remains constant, express the rate of change of the base with respect to the height.
anonymous
 4 years ago
An isosceles triangle has base B and height H. Assuming its area remains constant, express the rate of change of the base with respect to the height.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm getting 2A/h^2 Does that look right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0My reasoning: A= 1/2 b * h 2A = b * h b = 2A/h db/dh 2A/h = db/dh 2A * h^1 = 2A * h^2 = 2A/h^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Argh! Distributed wrongly.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Right, but you don't differentiate Area...only height.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Or am I wrong about this?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Doesn't it mean that if we keep the Area constant, at what rate does the base change respective of the height? That can't be 0, I wouldn't think.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0A solution using Mathematica is attached.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think I made a mistake.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, 2A/h^2 is the correct answer.
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