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anonymous
 4 years ago
h(x)=6xx^2 for x≥3
Express h−1(x) in terms of x.
anonymous
 4 years ago
h(x)=6xx^2 for x≥3 Express h−1(x) in terms of x.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry thats express h inverse in terms of x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can't be done fuction is not bijective

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[x^26x=y\]\[x^26x+3=y+3\]\[(xsqrt(3))^2=y+3\]\[x\sqrt(3)=\pm(y+3)^2\]\[x=\pm(y+3)^2+sqrt(3)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Necessary and compulsory condition for inversion is that the function has to be bijective
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