anonymous
  • anonymous
Solve the following quadratic equations. (hint: use factorization) HELP ME QUICK! please n^2+3n-12=6
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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aroub
  • aroub
n^2+3n-12-6=0 n^2+3n-18=0 (n+6)(n-3)=0 n=-6 , n=3
anonymous
  • anonymous
Thanks Thanks... would you help me with another one?
aroub
  • aroub
Sure!

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anonymous
  • anonymous
THANKS!!! -4k^2-8k-3=-3-5k^2
aroub
  • aroub
-4k^2+5k^2-8k-3+3=0 k^2-8k=0
aroub
  • aroub
I don't think you can factor it more..
aroub
  • aroub
or only : k(k-8)=0
aroub
  • aroub
So, k=0 , k=8
anonymous
  • anonymous
Its alright.., would you actually help me with my homework for tomorrow? :( I have lot of questions
aroub
  • aroub
I'll try my best =)
anonymous
  • anonymous
thanks :) so the next one is Solve for x: x^2+8x=0
aroub
  • aroub
x=-8 and x=0

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