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  • 4 years ago

How many real solutions does the equation x^2010 = 2009 have?

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  1. anonymous
    • 4 years ago
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    Two real solutions, +/- the quantity which is 2009 raised to the power (1/2010). The solutions are two (and +/-) because the power 2010 to which x is raised is an even power, and the result will be positive whether x is negative or positive. My calc gives me an answer: +/- 1.003790945 (truncated

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