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anonymous

  • 4 years ago

Differentiate (2x)/(1-3x^2)

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  1. anonymous
    • 4 years ago
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    quotient rule?

  2. anonymous
    • 4 years ago
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    i guess, thats all the problem says

  3. anonymous
    • 4 years ago
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    denominator will be \[(1-3x^2)^2\] that is the easy part

  4. anonymous
    • 4 years ago
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    numerator will be \[ (1-3x^2)\times 2-2x\times (-6x)\] then some algebra

  5. anonymous
    • 4 years ago
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    no that is wrong, i get \[\frac{6x^2-2}{(1-3x^2)^2}\]

  6. anonymous
    • 4 years ago
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    thanks, that is what i got too...just wanted to be sure, he never worked one like that

  7. anonymous
    • 4 years ago
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    yw

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spraguer (Moderator)
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