simplify - cos(π−θ)+sin(π/2 +θ)

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simplify - cos(π−θ)+sin(π/2 +θ)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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cos(theta)+cos(theta)=2cos(theta)
\[-\cos(\pi-\theta)=\cos \theta\]
Also \[\sin(\frac{\pi}{2} +\theta)=\cos \theta\]

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Other answers:

so the answer would be zero?
Depends on what theta is
no number to it
The answer is 2cos(theta) Did you substitute the values in?
is there supposed to be a neg sign in front of the cos? "simplify -cos(pi-A)"
i got it thank you
can you help me with this one
4sin6α/cos^2 3α−sin^2 3α

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