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anonymous
 4 years ago
how would you solve 4x^29/x^211x60 multiplied by x^216/2x+3
anonymous
 4 years ago
how would you solve 4x^29/x^211x60 multiplied by x^216/2x+3

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Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{4x^29}{x^211x60} \times \frac{x^216}{2x+3}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{(2x3)(2x+3)}{(x15)(x+4)} \times \frac{(x4)(x+4)}{2x+3}\]

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac{4x^29}{x^211x60} *\frac{x^216}{2x+3}\] let's factor we know \[a^2b^2=(a+b)(ab)\] so we have now \[\frac{(2x3)(2x+3)}{x^211x60} *\frac{(x4)(x+4)}{2x+3}\] let's factor x^211x60 let's find factor of 60 , whose sum is 11 15 and 4 x^215x+4x60 (x15)(x+4) now let's rewrite thr polynomial fraction given \[\frac{(2x3)(2x+3)}{(x15)(x+4)} *\frac{(x4)(x+4)}{2x+3}\] let's cancel the common terms \[\frac{(2x3)\cancel{(2x+3)}}{(x15)\cancel {(x+4)}} *\frac{(x4)\cancel{(x+4)}}{\cancel{2x+3}}\] we get finally \[\frac{(2x3)(x4)}{x15}\]

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1\[\frac{(2x3)(x4)}{x15}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok i forgot to factor the 4x^29. Thank you very much!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would the answer for 5x/x^27x+10 minus 4/x^225 be 5x4/x5?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328738038677:dw

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2\[\frac { \frac{1}{x}\frac{1}{(x+1)}}{x1}\] LCM of x and x+1 is x(x+1) \[\frac { \frac{x+1}{x(x+1)}\frac{x}{x(x+1)}}{x1}\] we get now \[\frac { \frac{1}{x(x+1)}}{x1}\] we get finally \[\frac 1 {{(x)(x+1)}(x1)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what happened to the 2?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.1Final answer: \[\frac{1}{x(x+1)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh ok now isee it Thanks again you guys have been a great help

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this is all part of this welcome back worksheet in pre cal and i'm not really good with complex fractions. I still have sin,cos,tan on my mind lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1328739265241:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Rationalizing the denominator
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